A meter stick of mass m is balanced on a pin as shown below. Find the...
The meter stick in the drawing below is at equilibrium. The mass
of the meter stick is 100g, and the meter stick is uniform.
B only please, thank you.
Ocm 80cm 100cm m a)The mass m is: A. 100g а. 50g b. 200g с. 150g d. none of the above b) Find the support force
A uniform meter stick of mass $M$ has a half-filled can of fruit juice of mass $m$ attached to one end. The meter stick and the can balance at a point 19.6 cm from the end of the stick where the can is attached. When the balanced stick-can system is suspended from a scale, the reading on the scale is 2.59 N. A.)Calculate the mass of the meter stick. B.)Calculate the mass of the can of juice.
Three masses are attached to a uniform meter stick, as shown in the figure. The mass of the meter stick is 0.5 kg and the masses to the left of the fulcrum are m - 4.8 kg and my 4.8 kg. Find the mass my need to be attached to the right end of the stick to balance the system. 30 cm 40 cm 30 cm
Procedure 1, 2, 3 Mass of a clamp: 21.5 True mass of meter stick: _133.6 g Center of mass of meter stick: _50 cm True weight of unknown mass: _212.99_ Procedure 4 Position of the 100-g mass: 10.0 cm Position of equilibrium: _30.9 cm Mass of the stick from method of torques: Procedure 5 Position of the 100-g mass: 10.0 cm Position of the 200-g mass: _90.0 cm Position of equilibrium of meter stick: Procedure 6 Position of unknown mass...
A uniform metal meter-stick is balanced with a 1.0 kg rock attached to the left end of the stick. If the support is located 0.25 m from the left end, what is the mass of the meter-stick? (Hint: meter-stick is 1 m long). 0.6 kg 2.0 kg 1.0 kg 3.0 kg
Suppose that a meter stick is balanced at its center. A 0.18 kg mass is then positioned at the 8-cm mark. At what cm mark must a 0.22 kg mass be placed to balance the 0.18 kg mass? Please help
Question3 1 pts For the meter stick shown in the figure shown below, the force F, is unknown and it acts at the 10- cm mark. F, is balanced by another force, F2- 70 N that acts at the 70- cm mark. What is the magnitude F1 in Newtons, about an axis through the point B? Please round your answer to one decimal place. 10 20 30 40 50 60 70 80 90 2
A uniform meter stick is balanced with the pivot located at the 60 cm mark. And a mass of 50 grams placed at the 85 cm mark. What is the mass of the meter stick?
Place an unknown mass at the 10 cm mark of the meter stick. Suspend from the other side a counter mass m2 = 300g and adjust its position until the system is in static equilibrium. Using, Στ = 0 calculate the unknown mass m². Remove the unknown mass and determine its mass on the laboratory balance. See Figure. This is the accepted mass. Calculate % error. % Error lexperimentalacceptedy 100 accepted X axis X X2 m m, m=? X =...
at With the meter stick on the support stand, suspend a gram mass m = 100g the 15-cm mark on the meter stick. Then adjust the lever arm for a gram mass m2 = 200g on the other side of the axis. See Figure. X axis X X2 m m2 Record the mass and position x as read on the meter stick and then record the lever arms. Compute the torques and find a percent difference between the clockwise (Tow)...