Question

R R2

A conductive bar 52 cm long slides on two parallel metal bars placed within it a magnetic field (directed inward) of magnitude 1077 G, as indicated in the figure. The ends of the bars are connected to two resistors, R1 = 101 Ω and R2 = 157 Ω. The conductive bar moves to the left at a constant speed of 6 m / s as shown in the figure.

a) determine magnitud of current that circulates trough R1 (in mA). Show direction

b) magnitude of current that goes trough R2 (in mA)Show direction

c) Power in R1 (mW)

d) Power in R2 (mW)

e) force needed to maintain the bar at a constant velocity (in mN) Show direction of force

Answer 1

B R2 RI Consider here magnetic field B indirected into the page. a lonductive bar of length L is at a distance & from left end. magnetic feux - BALOO BA = B(LR) BLK. Emfinchuud in the bar = – da at d It (BLU) - -BL da at - Blue Kaspeed of bar.

According RAR R 1 to the force on proton towards are y direction. that means towards I2 bottom. E anivalent Resistanu R= Rill R2. R and R2 are in parallel L = +22 R = R = RIRL R+R2 R12101R, R2 2 157. R = (101 (157) - 61.462. tolt 157 in magnitude E= Bele B = 1077AF 1077x10-4 T. L = 52cm = 528102 m. 6 m/s E = 1077 X10-4 x52x10-2x 6. to et 34 volt E lurrent I R or 68mDADE 61.46 5.5 810 3 Amp indulo emf I - current through 1 2 = current Resistance Ri Resistance R₂ through

2.153x103 Amp using lisent division rule I = IXR2 5.5810 3 x 157 Amp 101+ 157 RITR2 3-347m A Izz IXRI RitR2 5 5x10 3 x 101 Ano 101t157 2.153 mA Am current through Ri 3-347 mA (5 Current through R2 2.153.MA parer in R, P. = I R (3.347 x 103) X101 W 1.1 mw. d Am Power in Ri= 1.1 mr. power in R2 I2 R2 = (2.15 33x103) ² x 157w - 73 mW An power in R2 = 1.73 mr.