A. Assuming that register $14 has the value 8563, what is the value of $15 after...
A. Assuming that register $14 has the value 8563, what is the value of $15 after the following instruction is carried out:
srl $15 $14 4
Give the answer in decimal.
B. Assuming that register $10 has the value 9424, what is the value of $13 after the following instruction is carried out:
srl $13 $10 3
Give the answer in decimal.
C. Assuming that register $10 has the value 51, what is the value of $10 after the following instruction is carried out:
sll $10 $10 4
Give the answer in decimal.
D. Assuming that register $9 has the value 21, what is the value of $14 after the following instruction is carried out:
sll $14 $9 4
Give the answer in decimal.
Homework Answers
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A. Assuming that register $14 has the value 8563, what is the
value of $15 after...
Assuming that register EBX has an address of 0x20000000 and register ESI has the value of...
Assuming that register EBX has an address of 0x20000000 and register ESI has the value of “8,” what does the following instruction do? Describe what happens to each register and/or memory location (provide the address(es) and value(s)). Also, how many bits are moved by this move instruction? MOV [EBX+ESI], AX
. please trace the code including the value in every register 1. Express the instruction on...
.
please trace the code including the value in every register
1. Express the instruction on line 9 of the program in 32-bit
machine language, and if necessary, refer to the table in the
appendix.
2. Set 000beef00 to $ s0 as input and calculate the value of $
s0 at the end of each step (lines 9, 13, 17, 21, 25) when executing
the above program (binary or Write in hexadecimal).
3. Briefly explain the operation of the above...
PCSrc Add ALU Add result Shift left 2 Read register 1Read Read register 2 Write register Write da...
PCSrc Add ALU Add result Shift left 2 Read register 1Read Read register 2 Write register Write data RegWrite Read ALU operation MemWrite data 1 MemtoReg Zero ALU ALUAddresS data Instruction Registers Read Read Instruction MI IMI memory WriteData data memory 16 Sign- MemRead extend 3, (4 points) For question#2, in the datapath as shown in Fig. 1, assume that one of the following control signals has a stuch-at-0 fault, meaning that the signal is always 0, regardless of its...
QUESTION 15 What is the value of the CH register in hexadecimal after the following code...
QUESTION 15 What is the value of the CH register in hexadecimal after the following code executes? MOV ECX,0x11223344
please provide correct solutions. please write neat Problem 1: Assume the following value of ACCA (CPU register "...
please provide correct solutions. please write
neat
Problem 1: Assume the following value of ACCA (CPU register "A") and memory contents Answer the questions below. Explain all answers. (15 points) ACCA E4 memory Address Data Sc001 03 Sco02 C2 For the instruction ADDA SCO03 Sco03 FE a. Explain and show how this instruction is executed by the 68HC12 (6 points) the Coutents of SCo03 A and storing it back in A b. Show the values in the CCR register bits...
Q3 {30%) Given a shift register with 5 memory elements (D-type Flip Flops) having an initial cont...
Q3 {30%) Given a shift register with 5 memory elements (D-type Flip Flops) having an initial content of 000012, apply function number 45p in order to populate the empty cells of the table below. clock Register Content Namber (n decimal 5 6 10 12 13 14 15 16 17 18 19 20 21 23 24 25 26 27 28 30
Q3 {30%) Given a shift register with 5 memory elements (D-type Flip Flops) having an initial content of 000012, apply...
Cork price: 16 10 15 10 17 11 14 13 11 14 11 16 18 16...
Cork price: 16 10 15 10 17 11 14 13 11 14 11 16 18 16 10 17 14 14 16 7 10 12 19 15 16 14 9 12 21 13 10 16 12 16 13 17 17 13 14 18 11 12 15 16 13 18 16 17 12 12 14 9 11 14 19 13 11 17 11 13 15 14 18 18 18 12 10 11 13 14 11 14 18 13 13 19 17 14...
Could you please help me doing this? Slide #14: Slide #15 The question: ARM Assembly Language...
Could you please help me doing this?
Slide #14:
Slide #15
The question:
ARM Assembly Language label mnemonic operand1, operand2, operand3 comments R2+R1->R3 Loc ADD R3, R2 R1 Label is a symbolic reference to this instruction's address in memory. Mnemonic represents the operation to be performed .The number of operands varies, depending on each specific instruction. Some instructions have no operands at all. operand1 is typically the destination register, and operand2 and operand3 are source operands. operand2 is usually a...
Topics 1. MIPS instruction set architecture (ISA). 2. Performance. 3. MIPS datapath and control. Exercise 1...
Topics 1. MIPS instruction set architecture (ISA). 2. Performance. 3. MIPS datapath and control. Exercise 1 Consider the memory and register contents shown below. Registers Ox0100 FFF8 13 ($t 5) 14 ($t6) 0x0100 FFFC 0x0101 0000 Memory 0x0000 0000 0x0001 1100 0x0A00 со00 0x1234 4321 OxBAOO OOBB 15 OXAAAA 0000 0x1111 1010 0x7FFF FFFD 0x0100 FFFO 0x0101 0008 (St7) Ox0101 0004 16 ($80) 0x0101 0008 17 ($sl) Show what changes and give the new values in hexadecimal after the following...
6. An 8-bit shift register has the binary equivalent of the decimal number 46 stored in it What a...
6. An 8-bit shift register has the binary equivalent of the decimal number 46 stored in it What are the base-10 equivalent contents of the register after the following operations have been performed? For each case, assume the same initial state given. [15pts] (a) SHR 1 (b) SHL 1 (c) SHR 2 (d) ROR 2
6. An 8-bit shift register has the binary equivalent of the decimal number 46 stored in it What are the base-10 equivalent contents of the...
.
please trace the code including the value in every register
1. Express the instruction on line 9 of the program in 32-bit
machine language, and if necessary, refer to the table in the
appendix.
2. Set 000beef00 to $ s0 as input and calculate the value of $
s0 at the end of each step (lines 9, 13, 17, 21, 25) when executing
the above program (binary or Write in hexadecimal).
3. Briefly explain the operation of the above...
PCSrc Add ALU Add result Shift left 2 Read register 1Read Read register 2 Write register Write data RegWrite Read ALU operation MemWrite data 1 MemtoReg Zero ALU ALUAddresS data Instruction Registers Read Read Instruction MI IMI memory WriteData data memory 16 Sign- MemRead extend 3, (4 points) For question#2, in the datapath as shown in Fig. 1, assume that one of the following control signals has a stuch-at-0 fault, meaning that the signal is always 0, regardless of its...
please provide correct solutions. please write
neat
Problem 1: Assume the following value of ACCA (CPU register "A") and memory contents Answer the questions below. Explain all answers. (15 points) ACCA E4 memory Address Data Sc001 03 Sco02 C2 For the instruction ADDA SCO03 Sco03 FE a. Explain and show how this instruction is executed by the 68HC12 (6 points) the Coutents of SCo03 A and storing it back in A b. Show the values in the CCR register bits...
Q3 {30%) Given a shift register with 5 memory elements (D-type Flip Flops) having an initial content of 000012, apply function number 45p in order to populate the empty cells of the table below. clock Register Content Namber (n decimal 5 6 10 12 13 14 15 16 17 18 19 20 21 23 24 25 26 27 28 30
Q3 {30%) Given a shift register with 5 memory elements (D-type Flip Flops) having an initial content of 000012, apply...
Could you please help me doing this?
Slide #14:
Slide #15
The question:
ARM Assembly Language label mnemonic operand1, operand2, operand3 comments R2+R1->R3 Loc ADD R3, R2 R1 Label is a symbolic reference to this instruction's address in memory. Mnemonic represents the operation to be performed .The number of operands varies, depending on each specific instruction. Some instructions have no operands at all. operand1 is typically the destination register, and operand2 and operand3 are source operands. operand2 is usually a...
Topics 1. MIPS instruction set architecture (ISA). 2. Performance. 3. MIPS datapath and control. Exercise 1 Consider the memory and register contents shown below. Registers Ox0100 FFF8 13 ($t 5) 14 ($t6) 0x0100 FFFC 0x0101 0000 Memory 0x0000 0000 0x0001 1100 0x0A00 со00 0x1234 4321 OxBAOO OOBB 15 OXAAAA 0000 0x1111 1010 0x7FFF FFFD 0x0100 FFFO 0x0101 0008 (St7) Ox0101 0004 16 ($80) 0x0101 0008 17 ($sl) Show what changes and give the new values in hexadecimal after the following...
6. An 8-bit shift register has the binary equivalent of the decimal number 46 stored in it What are the base-10 equivalent contents of the register after the following operations have been performed? For each case, assume the same initial state given. [15pts] (a) SHR 1 (b) SHL 1 (c) SHR 2 (d) ROR 2
6. An 8-bit shift register has the binary equivalent of the decimal number 46 stored in it What are the base-10 equivalent contents of the...
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