Question

Apply Newton-Raphson method, to find the root of x, = 5cos2x which is near to x = 0.7 correct to four decimal places.
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Answer #1

Solving for x1, x2, x3.... until we get four common decimal digits. The four decimals digit matched for x7 and x8 so, value of x8 is where to stop further calculation and is the answer.

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Neuton Raphson Method f(xo) 143236.1759 2.1 52 2-462-2522- 5 cos(2x2452 3x2.52 10 sin 2x2452) 2.1452 9.140坪 1391 1.9353 19353-L1.9353-5 cos(2x1-9353 3x 9353+3C1·구나 55) +10 sinl2x 455) 9-7녀922 「구119) -5 Cos (2x)-구119) 3(1-귀19), 10 sin(2x1,구119) 9.389 6409-14.709)3-5cos C2x1-709) 3Ci3C1·구나 55) +10 sinl2x 455) 9-7녀922 「구119) -5 Cos (2x)-구119) 3(1-귀19), 10 sin(2x1,구119) 9.389 6409-14.709)3-5cos C2x1-709) 3Ciュ1,7083 3-140883)25c05 (2x483] [3040883)HOsin (2x)-구Z83) =), 70883 - Co.oo029) . 384 =1.70883+ 0.0000 31 329

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