Homework Answers
The calculation for the problem is as follows:
1. Given that: Pc=30 W
2. Modulation index m= 0.85
(a) Total power in any AM signal is given by:
Pt =Pc (1+m2/2)
Substituting values:
Pt = 30(1+0.852/2)
= 30(1+0.36125)
=30*1.36125
=40.8375W
Hence total power is: 40.8375W
(b)Power in side bands
Now total power is: 40.8375W
So total power in two side bands is 40.8375-30=10.8375W
So the power in each side band is 10.8375/2=5.41875W
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