In a certain chemical process, a lab technician supplies 251 J of heat to a system. At the same time, 64.0 J of work are done on the system by its surroundings. What is the increase in the internal energy of the system?
Since heat and work are both forms of energy. The first law of
thermodynamics states that
dE=dQ +dW =(Heat absorbed) + (work done on the system)
the increase in the internal energy of the system = 251 + 64 =315 J
In a certain chemical process, a lab technician supplies 251 J of heat to a system....
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