Question

3.Use two pointers ptr1 and ptr2 to display the product of the even numbers between 20 up to 30. #include <stdio.h> int main(void) int *ptr1, *ptr2, i, product

Answer 1

• POINTERS AND VARIABLES: Pointers in C language is a variable that stores/points the address of another variable. A Pointer in C is used to allocate memory dynamically i.e. at run time. The pointer variable might be belonging to any of the data type such as int, float, char, double, short etc. We need to dereference them with * operator to store value.

Here we use int * ptr; to declare a pointer and store address of a variable in it;

"POINTERS AND VARIABLES: �Pointers in C�language is a variable that stores/points the address of another variable. A�Pointer in C�is used to allocate memory dynamically i.e. at run time. The�pointer�variable might be belonging to any of the data type such as int, float, char, double, short etc. We need to dereference them with * operator to store value. Here we use int * ptr: to declare a pointer and store address of a variable in it: int * ptr: int I = 20: ptr = &i: printf(""%d"", * ptr) rightarrow VALUE OF VARIABLE�S ADDRESS IN ptr = 20 printf(}%d}, ptr) rightarrow VALUE STORED IN ptr(ADDRESS OF I) = 1000 printf(""%d"", &ptr): rightarrow ADDRESS OF ptr(1050) Using two pointers: #include < stdio.h > int main(void) { �int * ptr1,*ptr2: �int i = 20, product = 1: ptr1 =&i: //ptr1 refers to variable i = 20 which is the lower limit for mux ptr2 =&product: //ptr2 refers to variable product which will find the answer of //product of�"

• Using two pointers:

#include <stdio.h>

int main(void) {
  
   int * ptr1,*ptr2;
   int i=20,product=1;
   ptr1=&i; //ptr1 refers to variable i=20 which is the lower limit for mux
   ptr2=&product; //ptr2 refers to variable product which will find the answer of //product of all even numbers from 20 to 30

//*ptr1=20,*ptr2=1
  
   while(*ptr1<=30)
   {
   *ptr2=(*ptr2)*(*ptr1); //we multiply value from 20 to product=1 and add 2 to multiply all //even numbers till 30
   *ptr1=*ptr1+2;
   }
   printf("%d\n",product);
  
  
   return 0;
}

• CODE SCREENSHOT:

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• Using single pointer:

#include <stdio.h>

int main(void) {
  
   int * ptr1,*ptr2;
   int i=20,product=1;
   ptr1=&i;
  
   while(*ptr1<=30)
   {
   product=product*(*ptr1);
   *ptr1=*ptr1+2;
   }
   printf("%d\n",product);
  
   return 0;
}