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View Help Open in Desktop App Tell me what you want to do B ov A A .. Ev Ev E A Style 16. In the Hardy-Weinberg equation, p+2
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Ans16) heterozygous individuals

Explanation:In hardy Weinberg equation:

  • 2pq represents the genotype frequency of heterozygotesheterozygote.
  • p​​​​​​2 represent Genotype frequency of homozygous dominant while q​​​​​​2 represents Genotype frequency of homozygous recessive individuals.

Ans17) remain constant from one generation to the next so evolution does not occurs.

Explanation: Hardy weinberg equilibrium law states that allele frequencies remain constant from one generation to next generation in an ideal population which do not undergo evolution,mutation,genetic drift and population individual mated randomly.

Ans18) Artificial selection

Explanation: Artificial selection is a type of selection where human select for desired traits or features in agricultural plants or animals and allow the mating of plants and animals of selected trait to produce desired trait in short span of time.

Farmers and horticulturist bred broccoli, cauliflower ,Kale and cabbage from wild mustard plant through artificial selection because here interspecies mating occurs which was done by humans for their benefits so it is a kind of artificial selection .

While Evolution,genetic drift, natural selection, sexual selection are all natural phenomenon .

Ans19) existing beneficial mutations.

Explaination: if an environment changes rapidly then organism with already existing beneficial mutations will be more likely to survive and reproduce.

Neural mutations are those mutations which are neither harmful nor beneficial for an organism so so they play no role in Survival of organism during environment change .

Adaptation to environment and beneficial mutation production take time so so if environment changes rapidly then already existing beneficial mutations are more helpful for the survival and reproduction of an organism.

Ans20)32%

Explanation:

Dominant allele frequency=p=0.8

Recessive allele frequency=q=1-p=1-0.8=0.2

genotype frequency of heterozygotes=2pq=2x0.8x0.2=0.32

Percentage of heterozygotes=0.32x100=32%

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