3a. A dentist causes the bit of a high-speed drill to accelerate from an angular speed of 1.00×1041.00×104 rad/s to an angular speed of 3.30×1043.30×104 rad/s. In the process, the bit turns through 1.86×1041.86×104 rad. Assuming a constant angular acceleration, how long would it take the bit to reach its maximum speed of 7.80×1047.80×104 rad/s, starting from rest?
________s
3b. During a tennis serve, a racket is given an angular
acceleration of magnitude 120 rad/s2. At the top of the
serve, the racket has an angular speed of 13.0 rad/s. If the
distance between the top of the racket and the shoulder is 1.10 m,
find the magnitude of the total acceleration of the top of the
racket.
______ m/s2
3a. A dentist causes the bit of a high-speed drill to accelerate from an angular speed...
A dentist causes the bit of a high-speed drill to accelerate from an angular speed of 1.21E+4 rad/s to an angular speed of 3.07E+4 rad/s. In the process, the bit turns through 1.95E+4 rad. Assuming a constant angular acceleration, how long would it take the bit to reach its maximum speed of 7.84E+4 rad/s, starting from rest? 4.109 s Submit Answer Incorrect. Tries 1/7 Previous Tries starting from tant angular acceleromecular speed
A dentist's drill starts from rest and undergoes uniform angular acceleration for a period of 0.115 s until it turns at a rate of 2.15 ✕ 104 rev/min. A dentist's drill starts from rest and undergoes uniform angular acceleration for a period of 0.115 s until it turns at a rate of 2.15 x 104 rev/min. (a) What is the drill's angular acceleration (in rad/s2)? (Enter the magnitude.) rad/s2 (b) What is the angle (in radians) through which the drill...
A dentist's drill starts from rest. After 3.10 s of constant angular acceleration it turns at a rate of 2.80 ✕ 104 rev/min. (a) Find the drill's angular acceleration. _______ rad/s2 (b) Determine the angle (in radians) through which the drill rotates during this period. ________ rad
A dentist's drill starts from rest. After 3.20 s of constant angular acceleration it turns at a rate of 2.70 ✕ 104 rev/min. (a) Find the drill's angular acceleration. rad/s2 (b) Determine the angle (in radians) through which the drill rotates during this period. rad
A dentist's drill starts from rest. After 2.50 s of constant angular acceleration it turns at a rate of 2.55 ✕ 104 rev/min. (a) Find the drill's angular acceleration. rad/s2 (b) Determine the angle (in radians) through which the drill rotates during this period. rad
A dentist's drill starts from rest. After 4.60 s of constant angular acceleration it turns at a rate of 2.55 ✕ 104 rev/min. (a) Find the drill's angular acceleration. rad/s2 (b) Determine the angle (in radians) through which the drill rotates during this period. rad
A high speed drill bit rotating counter clockwise at 1200 rpm slows to a stop in 3.0 seconds A.) what is the drills angular acceleration in rad/sec^2? B.)How many revolutions does the drill bit make before it stops?
a. A rotating wheel requires 7.00 s to rotate 25.0 revolutions. Its angular velocity at the end of the 7.00 s interval is 97.0 rad/s. What is the constant angular acceleration of the wheel? b. A machine part rotates at an angular speed of 0.52 rad/s; its speed is then increased to 3.2 rad/s at an angular acceleration of 0.52 rad/s2. Find the angle through which the part rotates before reaching this final speed. c. A dentist's drill starts from...
A dentist's drill starts from rest. After 2.90 s of constant angular acceleration it turns at a rate of 2.75 ✕ 104 rev/min. (a) Find the drill's angular acceleration. (b) Determine the angle (in radians) through which the drill rotates during this period. rad
HELP!! 2. (-15 Points] DETAILS A dentist's drill starts from rest. After 3.40 s of constant angular acceleration it turns at a rate of 2.25 x 104 rev/min. (a) Find the drill's angular acceleration. rad/s2 (b) Determine the angle (in radians) through which the drill rotates during this period. rad