1) dQ = k A dT/L = 1.05*.3*1.5*(25-8)/1.2E-3=6694
2) dU = Q- W = 500-200 = 300 J
3) isothermal so dU = 0
so Q = W
so Q = 8.8 kJ
4) dU = Q - W = 300.0E3 - 2.8E5*1= 20 kJ
5) since volume is constant W = 0
so dU = Q = -800 kJ
6)
adiabatic so Q = 0
dU = Q -W = -8.0 kJ
1) Calculate the heat through a glass window that is 30.0 cm*150 cm in area and 1.20 mm&n
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