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In a population of 100 lizards, the “A” allele encodes for spots and is dominant over...

In a population of 100 lizards, the “A” allele encodes for spots and is dominant over the
“a” allele which encodes for strips. If non-random-mating occurred in this population, meaning lizards only
mated with other lizards with the same genotype, how would the allele and genotype frequencies change after
two generations of non-random mating?

A = 0.5

a = 0.5

I would really appreciate if you could provide an explanation for the steps. Thank you!

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Answer #1

We have A + a = 1 . This means it follows the hardy Weinberg law . Let's say A is p and a is q.

So allele frequency of AA = p 2= 0.25

Allele frequencies of Aa = 2pq = 0.50

Allele frequency of aa= q 2 = 0.25

These frequency won't change after any generations except there are any mutations or disaster in the population .

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