Question

D Question 7 1 pts A diode has a reverse saturation current of 10 pA and has n-1 and is operating at room temperature. Find the voltage drop in volts at a current of 4 mA D Question 8 1 pts A diode has n 1 and is operating at room temperature. When carrying a current of 14 mA the terminal voltage is measured at 0.65 V. What is the saturation current in pA? DQuestion9 1 pts A diode has n 1 and is operating at room temperature. When carrying a current of 0.2 mA the terminal voltage is 0.65 V. What is the terminal voltage in volts with a current of 8 mA?

Answer 1

It is given that is = 10 pa and n = 1 at room temperature T = 300 k, vt = 0.0256 v I = 4 mA From diode equation t is written as, I = I_z (e^pi - 1) = I_z e^v/vt v = v_t ln (i/I_z) = 0.0256 ln (4m/10 pA) = 0.507 v. The voltage drop in volt is = 0.507 V. n = 1, v = 0.65 v and i = 14 mA saturation current I_z = i/e^v/t = 14 m/e^x/t = 0.1315 pA n = 1, I = 0.2 mA v_1 = 0.65 v i2 = 8 mA, v_2 is to be calculated for i_1 = I_z e^v_1 /v_r i_2 = i_z e^v_2 /v_r it is written as, v_2 - v_1 = v_T ln (i_2 /i_1) = 0.0256 times ln (8m/0.2 m) = 0.0944 V v_2 = 0.7944 V. it is known that the diode voltage decrease by 2.5 mV/deg C