an enzyme-catalyzed reaction was carried out with the substrate concentration initially a thousand times greater than the Km for that substrate. After 9 minutes, 1% of the substrate had been converted to product, and the amount of product formed in the reaction mixture was 12micromols. If in a separate experiment, one third as much enzyme and twice as much substrate had been combined how long would it take for the same amount of product to form?
27 mins.
Given, the enzyme converts 1% substrate to product (12 mmols) in 9 minutes.
Now, the enzyme is reduced to 1/3rd and substrate is increased to twice the initial amount. The level of substrte increase does not affect the conversion rate.
Since 1 enzyme converts substrate to 12 mmol product in 9 minutes, 1/3 enzyme will require 3x9 minutes i.e. 27 minutes.
an enzyme-catalyzed reaction was carried out with the substrate concentration initially a thousand times greater than...
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At high (saturating) substrate concentrations, the rate of an enzyme-catalyzed reaction approaches Vmax. How close does the reaction rate actually get to Vmax? Determine how high (i.e. how many times Km) the substrate concentration must be for the reaction rate to be: a. 98% Vmax (show your work) (2) b. 99% Vmax (answer only) (1) c. 99.9% Vmax (answer only) (1)
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