Homework Answers
a) Cu = m2Cw(T - T2)/m1(T1 - T)
b) Cu = 1.5*4186*(31.2 - 23)/ 0.41(96 - 31.2)
= 1937.963
= 1938 J/kgK.
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Part A and Part B
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TW = 54°C in an insulated container. You add
ice at TI = -21°C to the container and the mix
reaches a final, equilibrium temperature of Tf
= 25°C. The specific heats of ice and water are
cI = 2.10×103J/(kg⋅°C) and
cW = 4.19×103 J/(kg⋅°C),
respectively, and the latent heat of fusion for water is
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