(20%) Problem 2: A piece of unknown material has a mass of m, = 0.79 kg and an initial temperature of Tu = 79°C. The s...
(0%) Problem 4: Soda from a ms= 12 oz can at temperature Ts = 11.5°C is poured in its entirely into a glass containing a mass m/= 0.19 kg amount of ice at temperature Ty=-18.5°C. Assume that ice and water have the following specific heats: c1=2090 J/(kg•°C) and cs = 4186 J/(kg:°C), and the latent heat of fusion of ice is Ir= 334 kJ/kg. In this problem you can assume that I kg of either soda or water corresponds to...
IIVIT ILI I ILUDLSU DL. U ZUI12.01.UUIII DUDULL. 11/21/2011.J.UUI1I LUDU. 12/UZUI11.J.UUI11 (0%) Problem 4: Soda from a m3= 12 oz can at temperature Tg = 15°C is poured in its entirety into a glass containing a mass mī= 0.13 kg amount of ice at temperature T,= -15.5°C. Assume that ice and water have the following specific heats: 0,= 2090 J/(kg.°C) and cs= 4186 J/(kg.°C), and the latent heat of fusion of ice is Lf= 334 kJ/kg. In this problem you...
Part A and Part B (13%) Problem 6: An unknown material, m = 0.41 kg, at a temperature of T-96 degrees C is added to a Dewer (an insulated container) which contains m,-1.5 kg of water at T2 = 23 degrees C. Water has a specific heat of c,-4186 J/(kg·K). After the system comes to equilibrium the final temperature is T= 31.2 degrees C. 50% Part (a) Input an expression for the specific heat of the unknown material. 0 BACKSPACE...
A 82 g cube of ice at 0°C is dropped into 1.0 kg of water that was originally at 80°C. What is the final temperature of the water after the ice has melted? The specific heat of ice is 2090 J/kg°C, and the latent heat of fusion of ice is 3.33x105 J/kg.
A 0.0575 kg ice cube at −30.0°C is placed in 0.617 kg of 35.0°C water in a very well insulated container, like the kind we used in class. The heat of fusion of water is 3.33 x 105 J/kg, the specific heat of ice is 2090 J/(kg · K), and the specific heat of water is 4190 J/(kg · K). The system comes to equilibrium after all of the ice has melted. What is the final temperature of the system?
A 0.0725 kg ice cube at −30.0°C is placed in 0.497 kg of 35.0°C water in a very well insulated container, like the kind we used in class. The heat of fusion of water is 3.33 x 105 J/kg, the specific heat of ice is 2090 J/(kg · K), and the specific heat of water is 4190 J/(kg · K). The system comes to equilibrium after all of the ice has melted. What is the final temperature of the system?
(20%) Problem 3: A thermos contains m = 0. 79 kg of tea at IT, = 31° C. Ice (m, = 0.055 kg, T, = 0° C) is added to it. The heat capacity of both water and tea is c 4186 J/(kg K), and the latent heat of fusion for water is L4= 33.5 x 104 J/kg. A 50% Part (a) Input an expression for the final temperature after the ice has melted and the system has reached thermal...
015 10.0 points A 20 g block of ice is cooled to -87°C. It is added to 566 g of water in an 64 g copper calorimeter at a temperature of 24°C. Find the final temperature. The specific heat of copper is 387 J/kg-°C and of ice is 2090 J/kg-PC. The latent heat of fusion of water is 3.33 x 10° J/kg and its specific heat is 4186 J/kg . °C. Answer in units of °C.
An unknown material has a normal melting/freezing point of -29.9 °C, and the liquid phase has a specific heat capacity of 164 J/(kg C°). One-tenth of a kilogram of the solid at -29.9 °C is put into a 0.100-kg aluminum calorimeter cup that contains 0.105 kg of glycerin. The temperature of the cup and the glycerin is initially 27.3 °C. All the unknown material melts, and the final temperature at equilibrium is 18.4 °C. The calorimeter neither loses energy to...
A 26 g block of ice is cooled to −62 ◦C. It is added to 569 g of water in an 80 g copper calorimeter at a temperature of 27◦C. Find the final temperature. The specific heat of copper is 387 J/kg · ◦C and of ice is 2090 J/kg · ◦C . The latent heat of fusion of water is 3.33 × 105 J/kg and its specific heat is 4186 J/kg · ◦C . Answer in units of ◦C.