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(20%) Problem 2: A piece of unknown material has a mass of m, = 0.79 kg and an initial temperature of Tu = 79°C. The specific

(0%) Problem 4: Soda from a ms = 12 oz can at temperature Ts = 18.5°C is poured in its entirety into a glass containing a mas

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€ Heat gained water = Heat lost by unknowmaterial mwew (Tf -TW) = mu cu (Tu-if) 1.4x4180734 19) = 0.79 C0 C 79-19) 14x4180 xb) ms es (Ts -Tf) = my CI (Tf -TI) & mif ma - Msis (TS -Tf) - MICI (TfTI) ht -0.057g m=0.34xu 0.34x4186 X18.5-0.18X 2090 x 19

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