Homework Answers
Part a )
Tf = 00C
Part b)
We know that,
Heat gained by ice = heat lost by soda
mI*cI*(0 - TI) + mmelted*Lf = mS*cS*(Ts-0)
mmelted = [ mS*cS*(Ts-0) - mI*cI*(0 - TI)]/Lf
mmelted = [ mS*cS*Ts + mI*cI* TI ] / Lf
Part c :
mmelted = [ mS*cS*Ts + mI*cI* TI ] / Lf
= [1*12/35.273 * 4186*15 + 0.13 * 2090* (-15.5 ] / 334 x 103
= [ 21361.38 - 4211.35 ] / 334000
= 0.05134 kg
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IIVIT ILI I ILUDLSU DL. U ZUI12.01.UUIII DUDULL. 11/21/2011.J.UUI1I LUDU. 12/UZUI11.J.UUI11 (0%) Problem 4: Soda from...
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