Question

30° 10cm 3cm cm 9cm 9 cm 10 cm 150 N Use the above diagram for P3. P3) If the winch is in static equilibrium, what is the mag

What is the magnitude of Force P?

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Answer #1

Find moment of each force 150N and P about x axis.

Moment of 150N = Force x lever arm

Lever arm = perpendicular distance to line of action of force

Moment = 150N * 9cm = 1350N.cm

Moment of P = P x Lever arm

Lever arm= perpendicular distance of line of action of P to x-axis

= 10.sin30 = 5cm

Moment of P=P*5cm = 5PN.cm

At equilibrium net moment about x will be zero.

Moment of P = Moment of P 5P = 1350 P= - = 270N 1350

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