Calculate the impedance at P.U. and pass the one-line diagram to impedance diagram. 44 1. (3)...
Calculate the impedance at P.U. and pass the one-line diagram to impedance diagram.
3.13 A single-line diagram of a three-phase power system is shown in Fig. 3.51. The ratings of the equipment are shown below Generator G: 100 MVA, 11 kV, Xi -X2-0.20 pu, Xo -0.05 pu Generator G2 : 100 MVA, 20 kV, Xi=X2=0.25 pu, Xo=0.03 pu, X,,-0.05 pu Transformer T: 100 MVA, 11/66 kV, Xi -X2-Xo 0.06 pu Transformer T2: 100 MVA, 11/66 kV, Xi-X2 = Xo 0.06 pu Line: 100 MVA, X,-X2 = 0.15 pu, Xo = 0.65 pu A...
The one-line diagram of a power system is given below. Draw the impedance diagram of the given system in per unit by selecting a common base of 200 MVA and 160kV on bus 4 for fault analysis. (20pts) 60 km 40 km Grounded Infinite Bus 4 6 5 60 km 60 km 60 km 80 km G BE 60 km 1 Tr N 3 G: 150 MVA, 10.8kV, X®G= 0.12 pu, Xa=0.8 pu Tr: 160 MVA Ratio: 11.2kV/154 kV Xtr=0.12...
Figure 1 Single line diagram b2 b3 b1 b4 grid Τι 13 A power system single line diagram is shown in Figure 1. The single line diagram shows a synchronous generator G connected to a large 50 Hz grid via its unit transformer T and a network of three transmission lines. Relevant details of the grid, transformer, generator and overhead lines are provided in Tables I,II,II & IV respectively. A double line to ground fault occurs at bus 3 Questions....
3) The single-line diagram of a three-phase power system is shown in Fig. 1. Equipment ratings are given as follows: G1 1,000 MVA, 15.0 kV, 20.18, o 0.07 pu G2 : 1,000 MVA. 15.0 kV, 攻=エ1 =エ2 = 0.20, ro = 0.10 pu G3 : 500 MVA, 13.8 kV. 1" = 띠 z2 = 0.15, zo 0.05 pu G4 : 750 MVA, 13.8 kV. ェd =ェ1 = 0.30, T2 = 0.40 ro = 0.10 pu Ti : 1,000 MVA. 15.0Δ/765Y...
2 - The three-phase power and line-line ratings of the electric power system shown in Figure 2 are given below. Ti T2 VA Line 2 G M Vm BE BE Figure 2 One-line diagram for problem 2 G: T: T2: Line: M: 60 MVA 50 MVA 50 MVA 20 kV 20/200 kV 200/20 kV 200 kV 18 kV X=9% X=10% X=10% Z=120+j2002 X=8% 43.2 MVA (a) Draw an impedance diagram showing all impedances in per unit on a 100-MVA base....
The three-phase power and line-line ratings of the electric power system shown in Figure 2 are given below T2 2 Line Vm G M 1 BA Figure 2 One-line diagram for problem 2 G: Ti: T2: Line: M: 60 MVA 50 MVA 50 MVA 20 kV 20/200 kV 200/20 kV 200 kV 18 kV X=9% X=10% X=10% Z=120+j2002 X=8% 43.2 MVA (a) Draw an impedance diagram showing all impedances in per unit on a 100-MVA base. Choose 20 kV as...
The three-phase power and line-line ratings of the electric power system shown in Figure 2 are given below. T1 T2 V. 1 2 vm 9 Line G M Figure 2 One-line diagram for problem 2 G: T1: 60 MVA 50 MVA 50 MVA T2: Line: M: 20 kV 20/200 kV 200/20 kV 200 kV 18 kV X=9% X=10% X=10% Z=120+j200 12 X=8% 43.2 MVA (a) Draw an impedance diagram showing all impedances in per unit on a 100-MVA base. Choose...
2. A single-line diagram of the power system considered is shown in Figure P2a, where negative- and zero-sequence reactances are also given. The neutrals of the generator and A-Y transformers are solidly grounded. The motor neutral is grounded through a reactance Xn = 0.05 per unit on the motor base. The per-unit zero-, positive and negative-sequence networks on a 100-MVA is shown in Figure P26, 13.8-kV base in the zone of the generator. a. Reduce the sequence networks to their...
A single line diagram of a power system is shown in Fig. 2. The system data with equipment ratings and assumed sequence reactances are given the following table. The neutrals of the generator and A-Y transformers are solidly grounded. The motor neutral is grounded through a reactance Xn 0.05 per unit on the motor base. Assume that Pre-fault voltage is takin as VF-1.0 ,0° per unit and Pre- fault load current and Δ-Y transformer phase shift are neglected In the...