3) The single-line diagram of a three-phase power system is shown in Fig. 1. Equipment ratings...
3.13 A single-line diagram of a three-phase power system is shown in Fig. 3.51. The ratings of the equipment are shown below Generator G: 100 MVA, 11 kV, Xi -X2-0.20 pu, Xo -0.05 pu Generator G2 : 100 MVA, 20 kV, Xi=X2=0.25 pu, Xo=0.03 pu, X,,-0.05 pu Transformer T: 100 MVA, 11/66 kV, Xi -X2-Xo 0.06 pu Transformer T2: 100 MVA, 11/66 kV, Xi-X2 = Xo 0.06 pu Line: 100 MVA, X,-X2 = 0.15 pu, Xo = 0.65 pu A...
Consider the single-line diagram of the three-phase power system shown in Figure 1. Component ratings are as follows: Generator G1: 750 MVA, 18 kV, X0.2 per unit Generator G2: 750 MVA, 18 kV, X 0.2 per unit Synchronous Motor M: 1,500 MVA, 20 kV, X-20% A-Y Transformers Ti, T2, T's, & T.: 750 MVA, 500 kV Y/20 kV A, X = 10% Y-Y Transformer T's 1,500 MVA, 500 kV Y/20 kV Y, X-10% ne L:X (a) Using bases of 100...
A simple three-phase power system is shown in Figure 2. Assume that the ratings of the various devices in this system are as follows: • Generators G1, G2: 40 MVA, 13.2 kV, = 0.15 pu, = 0.15 pu, = 0.08 • Generator G3: 60 MVA, 13.8 kV, = 0.20 pu, 0.20 pu, - 0.08 • Transformers T1, T2, T3, T4: 40 MVA, 13.8/138 kV, X1 = X2 = 0.10 pu, XO 0.08 pu Transformers T5, T6: 30 MVA, 13.8/138 kV, X1 = X2...
A single line diagram of a power system is shown in Fig. 2. The system data with equipment ratings and assumed sequence reactances are given the following table. The neutrals of the generator and A-Y transformers are solidly grounded. The motor neutral is grounded through a reactance Xn 0.05 per unit on the motor base. Assume that Pre-fault voltage is takin as VF-1.0 ,0° per unit and Pre- fault load current and Δ-Y transformer phase shift are neglected In the...
the single-line diagram of a three-phase power system is shown in figure 9.17. equipment ratings are given as follows: The inductor connected to Generator 3 neutral has a reactance of 0.05 per unit using generator 3 ratings as a base. Draw the zero-, positive-, and negative-sequence reactance diagrams using a 1000-MVA, 765-kV base in the zone of line 1-2. Neglect the Δ—Y. transformer phase shifts.
The single-line diagram of a three-phase power system is shown. Equipment ratings are given as follows: The inductor connected to generator 3 neutral has a reactance of \(0.05\) pu using generator 3 ratings as a base.1. Draw the zero-, positive-, and negative -sequence reactance diagrams using a \(1000 \mathrm{MVA}, 765 \mathrm{kV}\) base in the zone of line \(1-2\).2. Faults at bus 2 are of interest. Determine the Thevenin equivalent of each sequence network as viewed from the fault bus. Prefault voltage...
Assuming there is a FAULT at BUS 3, Determine the thevenin equivalent of each series network as viewed from the fault bus. Given: -Prefault voltage is 1.0 per unit -Prefault load currents and delta-wye transformer phase shifts are neglected Synchronous generators G1 1000 MVA 15 kVX"-X2 0.18, Xo 0.07 per unit G2 1000 MVA 15 kV X: X, = 0.20, X,-0.10 per unit G3 500 MVA 13.8 kV X: X,-0.15, X,-0.05 per unit G4 750 MVA 13.8 kV X,-0.30, X,-0.40,...
QUESTION 4. A single-line diagram of a power system is shown in Figure Q3 below, where negative and zero-sequence reactances are also given. The neutrals of the generator and A-Y transformers are solidly grounded. The motor neutral is grounded through a reactance X.=0.05 per unit on the motor base. Prefault voltage is VF1.05<Oº per unit whereas prefault load current is zero. Take A-Y transformer phase shifts into consideration. M Line tool X, - X2 - 200 100 MVA X =...
2. A single-line diagram of the power system considered is shown in Figure P2a, where negative- and zero-sequence reactances are also given. The neutrals of the generator and A-Y transformers are solidly grounded. The motor neutral is grounded through a reactance Xn = 0.05 per unit on the motor base. The per-unit zero-, positive and negative-sequence networks on a 100-MVA is shown in Figure P26, 13.8-kV base in the zone of the generator. a. Reduce the sequence networks to their...
The three-phase power and line-line ratings of the electric power system shown in Figure 2 are given below T2 2 Line Vm G M 1 BA Figure 2 One-line diagram for problem 2 G: Ti: T2: Line: M: 60 MVA 50 MVA 50 MVA 20 kV 20/200 kV 200/20 kV 200 kV 18 kV X=9% X=10% X=10% Z=120+j2002 X=8% 43.2 MVA (a) Draw an impedance diagram showing all impedances in per unit on a 100-MVA base. Choose 20 kV as...