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The three-phase power and line-line ratings of the electric power system shown in Figure 2 are given below T2 2 Line Vm G M 1

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1 airen in that question - The diagram Ti To Ng 1 2 Line BE + 38 M Given the data a: 60 MVA 20 KV X = 9% = 0.09 Tii 50 MVA 20Ti :- 100 (X pu) * (20) (2012 2) * 0-10 New 50 -0.2 Pu New T2 :- 100 (XPM) New 20 20 *ool 50 K pu) were 0.2pu Line: - Step-ab) Pony Giren data Motor ratting (5) 15 MVA Pf = 0.8 0.8 lagging Line-line terminal < = 18 kv voltage Step 6 line wuxvent (11NOW. calculating internal induce ene Ea = y + ) 1 * Xu -(1-07+ 10.7885) +30-5*0-15 fa = (1-07+j 0.8635) Pu or, 71-37 < = 1-37

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