Question
Per unit calculation
QUESTION 5 a) Define the Per Unit system and list three (3) main reasons of using Per Unit systemm. (5 marks) b) A three-bus
0 0
Add a comment Improve this question Transcribed image text
Answer #1

Per Unit Definition - System quantities defined as the fraction of the base quantities.

Three advantages -

1. Easy for handling large calculation

2. Per Unit impendence of Hv or Lv side of transformer remains the same

3 Per unit values can be easily used in digital computationT) 15Dで10 Ass 5 X 33%(03 3 33 - 33 A So 432 2. o 432 チs o ISOO 一0.1ーー O S33 0. 0619 。 1876 @xo . 33 Neus pu (T,Tc/ T,T4)、 0 2-12.12 z6 Fw line 25こ7575 0.33 0.33 0.2G6几 PU- 0 266 ·0619 12 .리 О.06(9 91 俞1 b 0G19 0.0619 숙1-14 vo 17.5 pv 1-16시구 .5 Termi

Add a comment
Know the answer?
Add Answer to:
QUESTION 5 a) Define the Per Unit system and list three (3) main reasons of using Per Unit system...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • INTRODUCTION TO POWER SYSTEM

    1. The one-line diagram of a three-pha  se power system is shown in Figure 3.29. Select a common base of 100 MVA and 15 kV on the motor side. Draw an impedance diagram with all impedances including the load impedance marked in per-unit. The manufacturer's data for each device is given as follow:The three-phase load at bus 4 absorbs 57 MVA, 0.6 power factor lagging at 10.45 kV. Line 1 and line 2 have reactances of 48.4 Ω and 65.43...

  • The three-phase power and line-line ratings of the electric power system shown in Figure 2 are...

    The three-phase power and line-line ratings of the electric power system shown in Figure 2 are given below T2 2 Line Vm G M 1 BA Figure 2 One-line diagram for problem 2 G: Ti: T2: Line: M: 60 MVA 50 MVA 50 MVA 20 kV 20/200 kV 200/20 kV 200 kV 18 kV X=9% X=10% X=10% Z=120+j2002 X=8% 43.2 MVA (a) Draw an impedance diagram showing all impedances in per unit on a 100-MVA base. Choose 20 kV as...

  • 2 - The three-phase power and line-line ratings of the electric power system shown in Figure...

    2 - The three-phase power and line-line ratings of the electric power system shown in Figure 2 are given below. Ti T2 VA Line 2 G M Vm BE BE Figure 2 One-line diagram for problem 2 G: T: T2: Line: M: 60 MVA 50 MVA 50 MVA 20 kV 20/200 kV 200/20 kV 200 kV 18 kV X=9% X=10% X=10% Z=120+j2002 X=8% 43.2 MVA (a) Draw an impedance diagram showing all impedances in per unit on a 100-MVA base....

  • The three-phase power and line-line ratings of the electric power system shown in Figure 2 are...

    The three-phase power and line-line ratings of the electric power system shown in Figure 2 are given below. T1 T2 V. 1 2 vm 9 Line G M Figure 2 One-line diagram for problem 2 G: T1: 60 MVA 50 MVA 50 MVA T2: Line: M: 20 kV 20/200 kV 200/20 kV 200 kV 18 kV X=9% X=10% X=10% Z=120+j200 12 X=8% 43.2 MVA (a) Draw an impedance diagram showing all impedances in per unit on a 100-MVA base. Choose...

  • Transformer TI : 50 MVA, 10 kV Y/138 kV Y, X=0.10 per unit; Transformer T2: 100 MVA, 15 kV D/138 kV Y, X-0.10 per unit; Each 138-kV line: X1-400 A three-phase short circuit occurs at bus 5,...

    Transformer TI : 50 MVA, 10 kV Y/138 kV Y, X=0.10 per unit; Transformer T2: 100 MVA, 15 kV D/138 kV Y, X-0.10 per unit; Each 138-kV line: X1-400 A three-phase short circuit occurs at bus 5, where the prefault voltage is 15 kV. Prefault load current is neglected. (a)Draw the positive-sequence reactance diagram in per-unit on a 100-MVA, 15-kV base in the zone of generator G2. Determine: (b) the The'venin equivalent at the fault, (c) the subtransient fault current...

  • Consider the single-line diagram of the three-phase power system shown in Figure 1. Component ratings are...

    Consider the single-line diagram of the three-phase power system shown in Figure 1. Component ratings are as follows: Generator G1: 750 MVA, 18 kV, X0.2 per unit Generator G2: 750 MVA, 18 kV, X 0.2 per unit Synchronous Motor M: 1,500 MVA, 20 kV, X-20% A-Y Transformers Ti, T2, T's, & T.: 750 MVA, 500 kV Y/20 kV A, X = 10% Y-Y Transformer T's 1,500 MVA, 500 kV Y/20 kV Y, X-10% ne L:X (a) Using bases of 100...

  • Consider the 4-bus power system shown in Fig. 1. The system parameters are given below: 50 MVA, 2...

    Please show all the clearly step Y11 ist j30 and Y44 isnt -j12.85 Consider the 4-bus power system shown in Fig. 1. The system parameters are given below: 50 MVA, 20 kV, X-2090 40 MVA, 20 kV, X-20%, X, = 5% 50 MVA, 20 kV Δ /110 kV Ý, X= 1090 50 MVA, 20 kV MI 10 kV Ý, X= 10% Xi-24.2 Ω Generator G: Motor M: Transformer T1 : Transformer T2 : Transmission line: 3 4 T2 nu)M Fig....

  • Fig Qshows the one-line diagram of a three-phase power system. As shown in Fig. Q3. the...

    Fig Qshows the one-line diagram of a three-phase power system. As shown in Fig. Q3. the two zones are connected by a 400 MVA, 240-kV/24-kV, Ý-A three phase transformer. The Y-A three phase transfonmer has an equivalent series impedance of ZTH - 1.2 + j1.6n per phase referred to the high voltage side (primary side). The three-phase power system can be studied with per unit quantities using base values of S-500 MVA and 240 kV in zone 1. By using...

  • 3) The single-line diagram of a three-phase power system is shown in Fig. 1. Equipment ratings...

    3) The single-line diagram of a three-phase power system is shown in Fig. 1. Equipment ratings are given as follows: G1 1,000 MVA, 15.0 kV, 20.18, o 0.07 pu G2 : 1,000 MVA. 15.0 kV, 攻=エ1 =エ2 = 0.20, ro = 0.10 pu G3 : 500 MVA, 13.8 kV. 1" = 띠 z2 = 0.15, zo 0.05 pu G4 : 750 MVA, 13.8 kV. ェd =ェ1 = 0.30, T2 = 0.40 ro = 0.10 pu Ti : 1,000 MVA. 15.0Δ/765Y...

  • Please answer the following question, box your answers, and show all work!! Thank you. 2 -...

    Please answer the following question, box your answers, and show all work!! Thank you. 2 - The three-phase power and line-line ratings of the electric power system shown in Figure 2 are given below. T T2 V Line 2 Vm G M Figure 2 One-line diagram for problem 2 60 MVA 20 kV 50 MVA 20/200 kV 50 MVA 200/20 kV 200 kV 43.2 MVA 18 kV TI: T: Line: M: X=9% X=10% X=10% Z=120+j2002 X=8% a) Draw an impedance...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT