Consider the single-line diagram of the three-phase power system shown in Figure 1. Component ratings are...
3) The single-line diagram of a three-phase power system is shown in Fig. 1. Equipment ratings are given as follows: G1 1,000 MVA, 15.0 kV, 20.18, o 0.07 pu G2 : 1,000 MVA. 15.0 kV, 攻=エ1 =エ2 = 0.20, ro = 0.10 pu G3 : 500 MVA, 13.8 kV. 1" = 띠 z2 = 0.15, zo 0.05 pu G4 : 750 MVA, 13.8 kV. ェd =ェ1 = 0.30, T2 = 0.40 ro = 0.10 pu Ti : 1,000 MVA. 15.0Δ/765Y...
G 3. Draw the reactance diagram for the power system shown in Figure.3. The ratings of generator, motor and transformers are given below. Neglect resistance and use a base of 50 MVA, 138 kV in the 40 Ohms Line :20MVA, 18 kV, X = 20% :20MVA, 18 kV, X = 20% Synchronous Motor: 30MVA 13.8Kv X = 20% 3-phase, Star-Star Transformer: 20 MVA, 138/20 kV, X= 10% 3-phase, Star-Delta Transformer: 20 MVA, 138/20 kV, X = 10% G2 y j4012...
3.13 A single-line diagram of a three-phase power system is shown in Fig. 3.51. The ratings of the equipment are shown below Generator G: 100 MVA, 11 kV, Xi -X2-0.20 pu, Xo -0.05 pu Generator G2 : 100 MVA, 20 kV, Xi=X2=0.25 pu, Xo=0.03 pu, X,,-0.05 pu Transformer T: 100 MVA, 11/66 kV, Xi -X2-Xo 0.06 pu Transformer T2: 100 MVA, 11/66 kV, Xi-X2 = Xo 0.06 pu Line: 100 MVA, X,-X2 = 0.15 pu, Xo = 0.65 pu A...
A single line diagram of a power system is shown in Fig. 2. The system data with equipment ratings and assumed sequence reactances are given the following table. The neutrals of the generator and A-Y transformers are solidly grounded. The motor neutral is grounded through a reactance Xn 0.05 per unit on the motor base. Assume that Pre-fault voltage is takin as VF-1.0 ,0° per unit and Pre- fault load current and Δ-Y transformer phase shift are neglected In the...
The three-phase power and line-line ratings of the electric power system shown in Figure 2 are given below T2 2 Line Vm G M 1 BA Figure 2 One-line diagram for problem 2 G: Ti: T2: Line: M: 60 MVA 50 MVA 50 MVA 20 kV 20/200 kV 200/20 kV 200 kV 18 kV X=9% X=10% X=10% Z=120+j2002 X=8% 43.2 MVA (a) Draw an impedance diagram showing all impedances in per unit on a 100-MVA base. Choose 20 kV as...
2 - The three-phase power and line-line ratings of the electric power system shown in Figure 2 are given below. Ti T2 VA Line 2 G M Vm BE BE Figure 2 One-line diagram for problem 2 G: T: T2: Line: M: 60 MVA 50 MVA 50 MVA 20 kV 20/200 kV 200/20 kV 200 kV 18 kV X=9% X=10% X=10% Z=120+j2002 X=8% 43.2 MVA (a) Draw an impedance diagram showing all impedances in per unit on a 100-MVA base....
The three-phase power and line-line ratings of the electric power system shown in Figure 2 are given below. T1 T2 V. 1 2 vm 9 Line G M Figure 2 One-line diagram for problem 2 G: T1: 60 MVA 50 MVA 50 MVA T2: Line: M: 20 kV 20/200 kV 200/20 kV 200 kV 18 kV X=9% X=10% X=10% Z=120+j200 12 X=8% 43.2 MVA (a) Draw an impedance diagram showing all impedances in per unit on a 100-MVA base. Choose...
the single-line diagram of a three-phase power system is shown in figure 9.17. equipment ratings are given as follows: The inductor connected to Generator 3 neutral has a reactance of 0.05 per unit using generator 3 ratings as a base. Draw the zero-, positive-, and negative-sequence reactance diagrams using a 1000-MVA, 765-kV base in the zone of line 1-2. Neglect the Δ—Y. transformer phase shifts.
QUESTION 4. A single-line diagram of a power system is shown in Figure Q3 below, where negative and zero-sequence reactances are also given. The neutrals of the generator and A-Y transformers are solidly grounded. The motor neutral is grounded through a reactance X.=0.05 per unit on the motor base. Prefault voltage is VF1.05<Oº per unit whereas prefault load current is zero. Take A-Y transformer phase shifts into consideration. M Line tool X, - X2 - 200 100 MVA X =...
Per unit calculation QUESTION 5 a) Define the Per Unit system and list three (3) main reasons of using Per Unit systemm. (5 marks) b) A three-bus power with two generator system is shown in figure Q2 (b). The 3-phase power and line-line voltage ratings are given below Ti T2 J40 2 Gi G2 j25 Ω 25 Ω Ty Figure Q2 (b) GI: 750 MVA, 18 kV, X 7% G2: 750 MVA, 18 kV, X-15% Motor: 1500 MVA, 20 kV,...