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Fig Qshows the one-line diagram of a three-phase power system. As shown in Fig. Q3. the two zones are connected by a 400 MVA, 240-kV/24-kV, Ý-A three phase transformer. The Y-A three phase transfonmer has an equivalent series impedance of ZTH - 1.2 + j1.6n per phase referred to the high voltage side (primary side). The three-phase power system can be studied with per unit quantities using base values of S-500 MVA and 240 kV in zone 1.

By using the common base of 500 MVA and 240 kV in zone 1. calculate a. The base value of the voltage in zone 2. [1 Mark] b. The base value of the inpedance in zone 1. [1 Mark] c. The base value of the impedance in zone 2. [1 Mark] d. All impedances including the load impedance in per-unit. [3 Marks]. By neglecting the American standard phase shift, and assuming that the line-to-line load voltage Vioad is equal to 22 kV: a. Draw the per-unit equivalent circuit. [2 Marks] b. Determine the per unit value of the current supplied by the generator; give your answer in polar form. [1 Mark]. c. By choosing the line-to-neutral load voltage as a reference, find the phasor voltage

in Time 1hour. 29 minutes 10 seconds Question completos A 400-MVA, 200-V 20-5V, three phase Y-Y transformer has an equivalent

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20 kV k Zone I R Zone 2 20 - 115.22 2 Base = 2.083 KA Zg: 0.8+51.0 Iload 20020 300 MVA 400 MVA 0.8 pf 0.012, toolbe Noad = 20pu © I lood = 15 2-36.87 °KA (Iload) pu = 0.12 23627/ (6 (IP), (I Load pu = 0.7 2 2 -36.8t pu Road = 0.7698 236.87° (d) Zin (

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