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PROBLEM 5 (20 pts]: Draw an impedance diagram for the electric power system given in the...
INTRODUCTION TO POWER SYSTEM
1. The one-line diagram of a three-pha se power system is shown in Figure 3.29. Select a common base of 100 MVA and 15 kV on the motor side. Draw an impedance diagram with all impedances including the load impedance marked in per-unit. The manufacturer's data for each device is given as follow:The three-phase load at bus 4 absorbs 57 MVA, 0.6 power factor lagging at 10.45 kV. Line 1 and line 2 have reactances of 48.4 Ω and 65.43...
Draw an impedance diagram for thr electric power system shown below showing all the impedances in...
Draw an impedance diagram for thr electric power system shown below showing all the impedances in per unit on a 100 MVA base. Choose 20 kV, as the voltage base for generator. The three-phase power and line ratings are given below. Calculate the short circuit current at bus No. 2.
The one-line diagram of a power system is given below. Draw the impedance diagram of the...
The one-line diagram of a power system is given below. Draw the impedance diagram of the given system in per unit by selecting a common base of 200 MVA and 160kV on bus 4 for fault analysis. (20pts) 60 km 40 km Grounded Infinite Bus 4 6 5 60 km 60 km 60 km 80 km G BE 60 km 1 Tr N 3 G: 150 MVA, 10.8kV, X®G= 0.12 pu, Xa=0.8 pu Tr: 160 MVA Ratio: 11.2kV/154 kV Xtr=0.12...
Problem #2: (40 points) The three-phase power and line- given below line ratings of the electric ...
Problem #2: (40 points) The three-phase power and line- given below line ratings of the electric power system shown are G:60 MVA, 20 kV, X = 9% Tr 50 MVA. 20/200 kV.x 1096 T2: 50 MVA, 20020 kV, X 10% M: 43.2 MVA, 18 kV, X 8% Line: 200 kV, Z 120+j200 Ti Line 00-MVA 1. Draw an impedance diagram showing all impedances in per-unit on a1 2. The motor is drawing 40 MVA, 0.8 power factor lagging at a...
Please show me step by step how to get load impedance in per-unit. New load is 1.05+1.4j per unit...
Please show me step by step how to get load impedance in
per-unit. New load is 1.05+1.4j per unit and new z load is 0.447
per unit
Consider the three-phase power system in the figure below. By selecting a common base of 100 MVA and 22 kV on the generator side, draw an impedance diagram showing all impedances, including the load impedance in per-unit. Lines 1 and 2 have series reactances of 48.4 and 65.43 2, respectively. At bus 4,...
Al power system is shown in the diagram below. A phase A-C fault occurs just before the A radi tr...
al power system is shown in the diagram below. A phase A-C fault occurs just before the A radi transmission line. Calculate the per-unit fault c pu. urrent in phases A and C. The fault impedance is O.001 Yg Ye TLine Load 0.1j 11kv/66kv x(+)-0.04j x()-0.04i 11 kv Kg(-)-005i Use Sbase 10 MVA. All impedances are given in pu and on 10 MVA base.
al power system is shown in the diagram below. A phase A-C fault occurs just before...
3.13 A single-line diagram of a three-phase power system is shown in Fig. 3.51. The ratings...
3.13 A single-line diagram of a three-phase power system is shown in Fig. 3.51. The ratings of the equipment are shown below Generator G: 100 MVA, 11 kV, Xi -X2-0.20 pu, Xo -0.05 pu Generator G2 : 100 MVA, 20 kV, Xi=X2=0.25 pu, Xo=0.03 pu, X,,-0.05 pu Transformer T: 100 MVA, 11/66 kV, Xi -X2-Xo 0.06 pu Transformer T2: 100 MVA, 11/66 kV, Xi-X2 = Xo 0.06 pu Line: 100 MVA, X,-X2 = 0.15 pu, Xo = 0.65 pu A...
The one line diagram of a three-phase power system is shown in Fig.8. Impedances are marked...
The one line diagram of a three-phase power system is shown in
Fig.8. Impedances are marked in per unit on a 100 MW, 400 kV base.
The Load at Bus 2 is S2 = 15.93 MW - j33.4Mvar, and at Bus 3 is S3
= 77 MW + j14 Mvar. It is required to hold the voltage at Bus 3 at
400 kV, Angle 0 degs. Working in per unit, determine the voltages
at Buses 2 and 1.
Q8: The...
The three-phase power and line-line ratings of the electric power system shown in Figure 2 are...
The three-phase power and line-line ratings of the electric power system shown in Figure 2 are given below T2 2 Line Vm G M 1 BA Figure 2 One-line diagram for problem 2 G: Ti: T2: Line: M: 60 MVA 50 MVA 50 MVA 20 kV 20/200 kV 200/20 kV 200 kV 18 kV X=9% X=10% X=10% Z=120+j2002 X=8% 43.2 MVA (a) Draw an impedance diagram showing all impedances in per unit on a 100-MVA base. Choose 20 kV as...
2 - The three-phase power and line-line ratings of the electric power system shown in Figure...
2 - The three-phase power and line-line ratings of the electric power system shown in Figure 2 are given below. Ti T2 VA Line 2 G M Vm BE BE Figure 2 One-line diagram for problem 2 G: T: T2: Line: M: 60 MVA 50 MVA 50 MVA 20 kV 20/200 kV 200/20 kV 200 kV 18 kV X=9% X=10% X=10% Z=120+j2002 X=8% 43.2 MVA (a) Draw an impedance diagram showing all impedances in per unit on a 100-MVA base....
Draw an impedance diagram for thr electric power system shown below showing all the impedances in per unit on a 100 MVA base. Choose 20 kV, as the voltage base for generator. The three-phase power and line ratings are given below. Calculate the short circuit current at bus No. 2.
The one-line diagram of a power system is given below. Draw the impedance diagram of the given system in per unit by selecting a common base of 200 MVA and 160kV on bus 4 for fault analysis. (20pts) 60 km 40 km Grounded Infinite Bus 4 6 5 60 km 60 km 60 km 80 km G BE 60 km 1 Tr N 3 G: 150 MVA, 10.8kV, X®G= 0.12 pu, Xa=0.8 pu Tr: 160 MVA Ratio: 11.2kV/154 kV Xtr=0.12...
Problem #2: (40 points) The three-phase power and line- given below line ratings of the electric power system shown are G:60 MVA, 20 kV, X = 9% Tr 50 MVA. 20/200 kV.x 1096 T2: 50 MVA, 20020 kV, X 10% M: 43.2 MVA, 18 kV, X 8% Line: 200 kV, Z 120+j200 Ti Line 00-MVA 1. Draw an impedance diagram showing all impedances in per-unit on a1 2. The motor is drawing 40 MVA, 0.8 power factor lagging at a...
Please show me step by step how to get load impedance in
per-unit. New load is 1.05+1.4j per unit and new z load is 0.447
per unit
Consider the three-phase power system in the figure below. By selecting a common base of 100 MVA and 22 kV on the generator side, draw an impedance diagram showing all impedances, including the load impedance in per-unit. Lines 1 and 2 have series reactances of 48.4 and 65.43 2, respectively. At bus 4,...
al power system is shown in the diagram below. A phase A-C fault occurs just before the A radi transmission line. Calculate the per-unit fault c pu. urrent in phases A and C. The fault impedance is O.001 Yg Ye TLine Load 0.1j 11kv/66kv x(+)-0.04j x()-0.04i 11 kv Kg(-)-005i Use Sbase 10 MVA. All impedances are given in pu and on 10 MVA base.
al power system is shown in the diagram below. A phase A-C fault occurs just before...
3.13 A single-line diagram of a three-phase power system is shown in Fig. 3.51. The ratings of the equipment are shown below Generator G: 100 MVA, 11 kV, Xi -X2-0.20 pu, Xo -0.05 pu Generator G2 : 100 MVA, 20 kV, Xi=X2=0.25 pu, Xo=0.03 pu, X,,-0.05 pu Transformer T: 100 MVA, 11/66 kV, Xi -X2-Xo 0.06 pu Transformer T2: 100 MVA, 11/66 kV, Xi-X2 = Xo 0.06 pu Line: 100 MVA, X,-X2 = 0.15 pu, Xo = 0.65 pu A...
The one line diagram of a three-phase power system is shown in
Fig.8. Impedances are marked in per unit on a 100 MW, 400 kV base.
The Load at Bus 2 is S2 = 15.93 MW - j33.4Mvar, and at Bus 3 is S3
= 77 MW + j14 Mvar. It is required to hold the voltage at Bus 3 at
400 kV, Angle 0 degs. Working in per unit, determine the voltages
at Buses 2 and 1.
Q8: The...
The three-phase power and line-line ratings of the electric power system shown in Figure 2 are given below T2 2 Line Vm G M 1 BA Figure 2 One-line diagram for problem 2 G: Ti: T2: Line: M: 60 MVA 50 MVA 50 MVA 20 kV 20/200 kV 200/20 kV 200 kV 18 kV X=9% X=10% X=10% Z=120+j2002 X=8% 43.2 MVA (a) Draw an impedance diagram showing all impedances in per unit on a 100-MVA base. Choose 20 kV as...
2 - The three-phase power and line-line ratings of the electric power system shown in Figure 2 are given below. Ti T2 VA Line 2 G M Vm BE BE Figure 2 One-line diagram for problem 2 G: T: T2: Line: M: 60 MVA 50 MVA 50 MVA 20 kV 20/200 kV 200/20 kV 200 kV 18 kV X=9% X=10% X=10% Z=120+j2002 X=8% 43.2 MVA (a) Draw an impedance diagram showing all impedances in per unit on a 100-MVA base....
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