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Al power system is shown in the diagram below. A phase A-C fault occurs just before the A radi tr...
A single line diagram of a power system is shown in Fig. 2. The system data with equipment ratings and assumed sequence reactances are given the following table. The neutrals of the generator and A-Y...
A single line diagram of a power system is shown in Fig. 2. The system data with equipment ratings and assumed sequence reactances are given the following table. The neutrals of the generator and A-Y transformers are solidly grounded. The motor neutral is grounded through a reactance Xn 0.05 per unit on the motor base. Assume that Pre-fault voltage is takin as VF-1.0 ,0° per unit and Pre- fault load current and Δ-Y transformer phase shift are neglected In the...
Use power base of 100MVA to change to per unit Consider the transmission system in figure...
Use power base of 100MVA to change to per unit
Consider the transmission system in figure 1 below Gen 1 Тx 2 Line 1 Gen 2 Tx3 Line 4 Line 3 R F Tx 1 Gen 3 Line 2 Figure 1 Impedance and winding details are:- Generators: Gen 1 132kV, Z=0+j12.5% on 25MVA Gen 2 132kV, Z= 0+j12.5% on 25 MVA 20KV, Z 0+j10% on 25 MVA A- connected windings Gen 3 Transformers Earthed Y windings (both sides) Earthed Y...
The diagram shows one phase of a 3-phase generation and distribution system. We would like to...
The diagram shows one phase of a 3-phase generation and
distribution system. We would like to determine the 12 kV short
circuit (maximum) current at the indicated location attributed to
the generation, in the event of a fault.
For this question, we work in the per unit pu system.
a. We pick S(base)=100 MVA, and V(base) = 12 kV. Then I(base)
and Z(base) are fixed. The 12 kV of the transformer secondary is
line-neutral voltage since this is a grounded...
PROBLEM 5 (20 pts]: Draw an impedance diagram for the electric power system given in the...
PROBLEM 5 (20 pts]: Draw an impedance diagram for the electric power system given in the Figure 4 showing all impedances in per unit on a 100MVA base. Choose 20/200 kV as the voltage base. If there is a three-phase to ground solid fault at the load bus, what will be fault current taken from generator 1. The three-phase power and line-line ratings are given below. Gl: 90 MVA, 20 kV, X = 9%; TR1: 80 MVA, 20/200 kV, X...
The one-line diagram of a simple power system is shown in Figure 1. The neutral of...
The one-line diagram of a simple power system is shown in Figure 1. The neutral of each generator is grounded through a current-limiting reactor of 0.25/3 per unit on a 100-MVA base. The system data expressed in per unit on a common 100-MVA base is tabulated below. The generators are running on no-load at their rated voltage and rated frequency with their emfs in phase. Determine the fault current for the following faults giving Zo = 0.35, Z = 0.22...
3.13 A single-line diagram of a three-phase power system is shown in Fig. 3.51. The ratings...
3.13 A single-line diagram of a three-phase power system is shown in Fig. 3.51. The ratings of the equipment are shown below Generator G: 100 MVA, 11 kV, Xi -X2-0.20 pu, Xo -0.05 pu Generator G2 : 100 MVA, 20 kV, Xi=X2=0.25 pu, Xo=0.03 pu, X,,-0.05 pu Transformer T: 100 MVA, 11/66 kV, Xi -X2-Xo 0.06 pu Transformer T2: 100 MVA, 11/66 kV, Xi-X2 = Xo 0.06 pu Line: 100 MVA, X,-X2 = 0.15 pu, Xo = 0.65 pu A...
Power System
A simple three-phase power system is shown in Figure 2. Assume that the ratings of the various devices in this system are as follows: • Generators G1, G2: 40 MVA, 13.2 kV, = 0.15 pu, = 0.15 pu, = 0.08 • Generator G3: 60 MVA, 13.8 kV, = 0.20 pu, 0.20 pu, - 0.08 • Transformers T1, T2, T3, T4: 40 MVA, 13.8/138 kV, X1 = X2 = 0.10 pu, XO 0.08 pu Transformers T5, T6: 30 MVA, 13.8/138 kV, X1 = X2...
Question 4 The power system shown is supplying a balanced wye-grounded resistive load that consumes the...
Question 4 The power system shown is supplying a balanced wye-grounded resistive load that consumes the MW at 1.1 kV. An SLG fault occurs at bus 3. Determine the fault current and the voltages at the fault point. Assume that the fault resistance is 6.6 2. The equipment parameters are shown in the figure. 3 4 2 (1 (1 + j5) 2 10 MW Tuto 20 MVA 22/1.1 kV X = X2 = Xo = 0.05 pu Generator 30 MVA...
The component parameters for the power system shown in Figure 2 are given in Table 1. The pre-fau...
The component parameters for the power system shown in Figure 2 are given in Table 1. The pre-fault voltage is 120° pu and Zx-j0.1 pu. Table 1 Ratings X2-Xi (pu)Xo (pu) 0.05 0.10 0.20 0.20 Components G1, G2 200 MVA, 20 kV 0.10 0.10 0.10 0.10 T1, T2, T3200 MVA, 20/200 kV L1 200 MVA, 200 kV し2 200 MVA, 20 kV (a) Draw the three sequence networks and determine the per-unit Thevenin impedance of each sequence network seen from...
Fig Qshows the one-line diagram of a three-phase power system. As shown in Fig. Q3. the...
Fig Qshows the one-line diagram of a three-phase power system.
As shown in Fig. Q3. the two zones are connected by a 400 MVA,
240-kV/24-kV, Ý-A three phase transformer. The Y-A three phase
transfonmer has an equivalent series impedance of ZTH - 1.2 + j1.6n
per phase referred to the high voltage side (primary side). The
three-phase power system can be studied with per unit quantities
using base values of S-500 MVA and 240 kV in zone 1.
By using...
A single line diagram of a power system is shown in Fig. 2. The system data with equipment ratings and assumed sequence reactances are given the following table. The neutrals of the generator and A-Y transformers are solidly grounded. The motor neutral is grounded through a reactance Xn 0.05 per unit on the motor base. Assume that Pre-fault voltage is takin as VF-1.0 ,0° per unit and Pre- fault load current and Δ-Y transformer phase shift are neglected In the...
Use power base of 100MVA to change to per unit
Consider the transmission system in figure 1 below Gen 1 Тx 2 Line 1 Gen 2 Tx3 Line 4 Line 3 R F Tx 1 Gen 3 Line 2 Figure 1 Impedance and winding details are:- Generators: Gen 1 132kV, Z=0+j12.5% on 25MVA Gen 2 132kV, Z= 0+j12.5% on 25 MVA 20KV, Z 0+j10% on 25 MVA A- connected windings Gen 3 Transformers Earthed Y windings (both sides) Earthed Y...
The diagram shows one phase of a 3-phase generation and
distribution system. We would like to determine the 12 kV short
circuit (maximum) current at the indicated location attributed to
the generation, in the event of a fault.
For this question, we work in the per unit pu system.
a. We pick S(base)=100 MVA, and V(base) = 12 kV. Then I(base)
and Z(base) are fixed. The 12 kV of the transformer secondary is
line-neutral voltage since this is a grounded...
PROBLEM 5 (20 pts]: Draw an impedance diagram for the electric power system given in the Figure 4 showing all impedances in per unit on a 100MVA base. Choose 20/200 kV as the voltage base. If there is a three-phase to ground solid fault at the load bus, what will be fault current taken from generator 1. The three-phase power and line-line ratings are given below. Gl: 90 MVA, 20 kV, X = 9%; TR1: 80 MVA, 20/200 kV, X...
The one-line diagram of a simple power system is shown in Figure 1. The neutral of each generator is grounded through a current-limiting reactor of 0.25/3 per unit on a 100-MVA base. The system data expressed in per unit on a common 100-MVA base is tabulated below. The generators are running on no-load at their rated voltage and rated frequency with their emfs in phase. Determine the fault current for the following faults giving Zo = 0.35, Z = 0.22...
3.13 A single-line diagram of a three-phase power system is shown in Fig. 3.51. The ratings of the equipment are shown below Generator G: 100 MVA, 11 kV, Xi -X2-0.20 pu, Xo -0.05 pu Generator G2 : 100 MVA, 20 kV, Xi=X2=0.25 pu, Xo=0.03 pu, X,,-0.05 pu Transformer T: 100 MVA, 11/66 kV, Xi -X2-Xo 0.06 pu Transformer T2: 100 MVA, 11/66 kV, Xi-X2 = Xo 0.06 pu Line: 100 MVA, X,-X2 = 0.15 pu, Xo = 0.65 pu A...
Question 4 The power system shown is supplying a balanced wye-grounded resistive load that consumes the MW at 1.1 kV. An SLG fault occurs at bus 3. Determine the fault current and the voltages at the fault point. Assume that the fault resistance is 6.6 2. The equipment parameters are shown in the figure. 3 4 2 (1 (1 + j5) 2 10 MW Tuto 20 MVA 22/1.1 kV X = X2 = Xo = 0.05 pu Generator 30 MVA...
The component parameters for the power system shown in Figure 2 are given in Table 1. The pre-fault voltage is 120° pu and Zx-j0.1 pu. Table 1 Ratings X2-Xi (pu)Xo (pu) 0.05 0.10 0.20 0.20 Components G1, G2 200 MVA, 20 kV 0.10 0.10 0.10 0.10 T1, T2, T3200 MVA, 20/200 kV L1 200 MVA, 200 kV し2 200 MVA, 20 kV (a) Draw the three sequence networks and determine the per-unit Thevenin impedance of each sequence network seen from...
Fig Qshows the one-line diagram of a three-phase power system.
As shown in Fig. Q3. the two zones are connected by a 400 MVA,
240-kV/24-kV, Ý-A three phase transformer. The Y-A three phase
transfonmer has an equivalent series impedance of ZTH - 1.2 + j1.6n
per phase referred to the high voltage side (primary side). The
three-phase power system can be studied with per unit quantities
using base values of S-500 MVA and 240 kV in zone 1.
By using...
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