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Consider the three-phase power system in the figure below. By selecting a common base of 100 MVA and 22 kV on the generator s

Please show me step by step how to get load impedance in per-unit. New load is 1.05+1.4j per unit and new z load is 0.447 per unit

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2 Zreus)(p.uj (p.uj X-ㄧ - Zotd 身国 T. foad 3 22) ー0.2 p.u 0.08 Pu 2 S 2212 2. to 0.o6 x 0.05 p.U 26 R, T3 0.1667 р.Jn e (22o ky)e o0mvA/ ↑ r lar (fnm @,e gren) 21169 n 749 Duin pu 丿 line Em tine@

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