Question

102 Viewing Saved Work Revert to Last Response 0/15 points Previous Answers My Ne Given the following balanced equation... 4NH3 + 702 → 4NO2 + 6H20 If 0.641 moles of ammonia is reacted with 0.706 moles of oxygen, how many moles of excess reactant remains after the reaction is complete? X mol Submit Answer Practice Another Version

Answer 1

according to balanced reaction 4 mol NH3 react with 7 mol O2
so mol ratio of O2 :NH3 = 7:4

mols of NH3 present = 0.641 mol
mols o O2 present = 0.706 mols
So 0.706 mols O2 will consume with 4/7* 0.706 mol NH3 [since mole ratio is 7:4

moles of NH3 consumed = 0.403428 mols

Thus few mols of NH3 will remain unreacted. Hence NH3 is the excess reactant

Mols of NH3 remaining= mols of NH3 present- mols of NH3 reacted
= 0.641 mols-0.403428 mols = 0.238 mols

Answer : 0.238 mols

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