If the potential of a hydrogen electrode based on the half reaction 2H+(aq)+2e−→H2(g) is 0.00V at...

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If the potential of a hydrogen electrode based on the half reaction 2H+(aq)+2e−→H2(g) is 0.00V at...

If the potential of a hydrogen electrode based on the half reaction 2H+(aq)+2e−→H2(g) is 0.00V at pH 0.00, what is the potential of the same electrode at pH = 4.00?

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Answer 1

Answer #1

2H+(aq)+2e−→H2(g)

number of electrons transfered = 2 = n

Eo = 0.00 V

pH = 4.00

[H+] = 10^-4 M = 1.0 x 10^-4 M

E = Eo - 0.05916 / n * log 1/ [H+]^2

E = 0.00 - 0.05916 / 2* log 1/ [10^-4^2]

E = - 0.237 V --------------------------------------------------> answer

note : do not forget to enter negative sign in your answer.

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Answer 2

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If the potential of a hydrogen electrode based on the half reaction 2H+(aq)+2e−→H2(g) is 0.00V at...

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