Physics

Question

Question

A force of 40.0 N is applied in the positive x-direction to a block of mass 8.75 kg, at rest on a frictionless surface.

(a)

What is the block's acceleration (in m/s²)? (Indicate the direction with the sign of your answer.)

(b)

How fast is it going (in m/s) after 5.50 s?

Answer 1

Answer #1

F=ma 40 = 8.75 x a a = 40/8.75 a = 4.57 (b) v = a x t v = 4.57 x 5.5 v = 25.135ms^-1

answered by: Franklin77

Answer 2

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