what is the blocks velocity at point D ?
Initially at rest, a block of mass 20 kg starts to slide down a frictionless hill. Based on the drawing, determine the answers to the questions below. hA = 120m hC = 90m hB = 30m hD = 0m
Homework Answers
SOLUTION :
At A, only P. E. Is there = m g hA = 20*9.8* 120 = 23520 J
At D, only K.E. is there = 1/2 m v^2 = 1/2 * 20 * v^2 = 10 v^2 J
As per conservation of energy :
K.E. gained = P.E. lost
=> 10 v^2 = 23520
=> v = sqrt(23520 / 10) = 48.50 meter/sec.
Hence, velocity at point D will be 48.50 m/sec^2 (ANSWER).
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