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Hello, can you please help me understand this problem? Thank you!
3. Let V be finite dimensional vector space. T is a linear transformation from V into W and E is a subspace of V and F is a s
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To V W is a linear transformation E EV is Ecw is a a subslouce of v. subsloace f w . THCF) = SUEVIT(4) CF ? T(E) = Swew/w = THence T (F) is a subspace of v. Claim - dim (T(F)) = dim (ken (T)) & dim (En Im (T)) Restrict T on T-(F) T: T(F) > W (T is rXE Kes(T) Т(x) = 0 T(x) E F 2) чет-ғ) т сx) = T(x) a x ekon (т) а кол ст) с коят) зо кар (т) = кол (т) — and Im (T)= Im (1)XEV. Im T C Im (T) OF y G Im (T) n F =) y E F & T (2) B = y for some -) με T (6) =) T (X) = T (x1=g a) y E Im CT) = Im (Claim - T(E) is subspace of w се в =) TOOE TCE) 7 Ow E T(E) Alence T(E) 78 det W, W₂ ET(E) y T(4)=W, . T (W) = W₂ when YEE aNow Restrict Tan E, say Th T E 70 w . by Rank nullity Theorem, eim (E ) = dim (Kes (T) + dim(Inte; Ker (7) = Kes (T) neSo we we gat Ken (1)= Ken Il ne - also Im (T) = T(E) ge Im (T) = I x GE such that - T(x) = y 2) XEE & T(x) = y 3) lyc TCbut 2 and (3) in eg. we gat dim (e) = dim ET CC)) + dim (kest 105) V = w z IP TCP(x)) = xp (x) E = FER = dim (E) = dim (F.) =xplone) e Pie plex) = * (constert) =) p(x) bla) ? at kn E span £t, & 7 = P, 5) FTCA) = P11 dim fpi= 2 = dim (7(F7) ker C) =Im (T) = span {x,x2,237 dim (Im ()) = 3 ਬਿਨਾ . Fn Im (A) = P n Im (T) = span {n} dim (En Im (T)) = 1 Fist esi verificatice ..

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