Question

Two steel plates, each 5/16 inch thick, are to be fillet-welded to a third one that is sandwiched between them. The width of each of the first two plates is 4 inches, whereas the width of the third one is 6 inches. The two plates overlap the third one by 6 inches, and an E7014 electrode (allowable tensile strength = 21,000 psi) is to be used. If the joint is to withstand a load of 190,000 pounds, use a sketch to illustrate a design for this joint and provide all calculations.

Answer 1

Answer: Given that, Two steel plates thick = 5/16 inch Finnst a plates width - 4 inch thind plate width = 6 inch T: allowable tensile strength = 21000psi load F 190,000 pounds Noce consider relation, Sketch T= 1,414 hindi 4 inch h = 1.414 - - - - 15/16 inch Substitute values h=1,414 x 190000 21000 X 4 6 inch h 268660 84000 h = 3.198 inch. Fillet weld Height is 3.198 in.