The beam shown below is subjected to a uniformly distributed load, w, over its entire length. What is the largest value of w that the beam can withstand prior to collapse? For simplicity, you may assume that w includes the weight of the beam itself.
Use ACI 318-14 building code requirements for structural concrete
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The beam shown below is subjected to a uniformly distributed
load, w, over its entire length....
The simply supported beam of length L is subjected to uniformly distributed load of w and...
The simply supported beam of length L is subjected to uniformly distributed load of w and a vertical point load P at its middle, as shown in Figure Q3. Both young's modulus and second moment of area of this structure are given as E and I. Please provide your answers in terms of letters w, P,L,1, E. Self-weight of the beam is neglected. P W L/2 L/2 Figure Q3 (a) Determine the reactions, bending moment equation along the beam and...
A 26.0 ft. simply supported beam is subjected to factored uniformly distributed load of wa equal ...
A 26.0 ft. simply supported beam is subjected to factored uniformly distributed load of wa equal to 6.0 kips/t. Beam properties are as follows: b-14 in, d-24 in, 4,000 psi (normal-weight concrete) and fy -60,000 psi. Design shear reinforcement for the entire beam (you can use symmetry if applicable). Use two different spacings over the beam length to come up with economical design. Perform all necessary checks and calculations. Draw final design for shear ma reinforcement indicating distribution (i.e, lengths,...
The reinforced concrete beam shown in Figure-2 is to be subjected to the following uniformly distributed...
The reinforced concrete beam shown in Figure-2 is to be subjected to the following uniformly distributed loads over the entire length: DL = 14 kn/m (including self-weight) and LL = 20kN/m, fc = 32 MPa. For architectural reasons the beam width is set at 500 mm. Determine the effective depth required if ku = 0.25 for the section of maximum positive bending moment. Then design the reinforcement required. zin Figure-2
The beam having a cross-section as shown is subjected to the distributed load w (1) Calculate...
The beam having a cross-section as shown is subjected to the distributed load w (1) Calculate the moment of inertia, I (2) If the allowable maximum normal stress ơmax-20 MPa, determine the largest distributed load 5. w. (3) If w 1.5 kN/m, determine the maximum bending stress in the beam. Sketch the stress distribution acting over the cross-section. 100 mm 50mm 120 mm 3 m50 mm 3 m
Q2 The 10 m long simply supported beam is subjected to a uniformly distributed load w...
Q2 The 10 m long simply supported beam is subjected to a uniformly distributed load w = 10 kN/m throughout and a point load P =10 kN at the midspan of the beam, as shown in Figure Q2 (a). The cross section of this beam is depicted in Figure Q2 (b), which consists of three equal rectangular steel members. Self-weight of the beam is neglected. 30 mm P= 10 KN W = 10 kN/m 200 mm 5 m 5 m...
Q2 The 10 m long simply supported beam is subjected to a uniformly distributed load w...
Q2 The 10 m long simply supported beam is subjected to a uniformly distributed load w = 10 kN/m throughout and a point load P =10 kN at the midspan of the beam, as shown in Figure Q2 (a). The cross section of this beam is depicted in Figure Q2 (b), which consists of three equal rectangular steel members. Self-weight of the beam is neglected. 30 mm P = 10 kN W = 10 kN/m 200 mm 5 m 5...
Q2 The 10 m long simply supported beam is subjected to a uniformly distributed load w...
Q2 The 10 m long simply supported beam is subjected to a uniformly distributed load w = 10 kN/m throughout and a point load P =10 kN at the midspan of the beam, as shown in Figure Q2 (a). The cross section of this beam is depicted in Figure Q2 (b), which consists of three equal rectangular steel members. Self-weight of the beam is neglected. 30 mm P = 10 kN w = 10 kN/m 200 mm 5 m 5...
The Beam shown will be subjected to a concentrated live load of 100kN, a uniformly distributed...
The
Beam shown will be subjected to a concentrated live load of 100kN,
a uniformly distributed live load of 50kN/m and a uniformly
distributed dead load of 20kN/m.
45.) determine the maximum reaction at B
46.) determine the maximum positive shear at C
47.) determine the maximum negative moment at B
The beam shown will be subjected to a concentrated live load of 100 KN, a uniformly distributed live load of 50 kN/m and a uniformly distributed dead load of...
Questions 5-8 A steel frame shown below is subjected to combined uniformly distributed gravity load (w...
Questions 5-8
A steel frame shown below is subjected to combined uniformly distributed gravity load (w 2 kips/f) and a horizontal earthquake load of H-10 kips Both the beams and the columns are made of W12x120 section having a yield strength of F 45 ksi. The Young's modulus of steel s E-29,000 ksi. The distributed load w is used to simulate the self-weight of the beam, the load transferred from roof slab, as well addition superimposed dead loads. The self-weigh...
The below wooden double overhanging beam is under a uniformly distributed load W. The wood is...
The below wooden double overhanging beam is under a uniformly distributed load W. The wood is weak along the orientation of the grain (or wood cell fibres) that makes an angle of 30° with the horizontal (see figure). The maximum shear stress on a plane parallel to the grain that the wood can sustain is t,max = 5 MPa, and the maximum normal stress of wood is omax = 25 MPa. The Young modulus of this wood is E=15 GPa....
The simply supported beam of length L is subjected to uniformly distributed load of w and a vertical point load P at its middle, as shown in Figure Q3. Both young's modulus and second moment of area of this structure are given as E and I. Please provide your answers in terms of letters w, P,L,1, E. Self-weight of the beam is neglected. P W L/2 L/2 Figure Q3 (a) Determine the reactions, bending moment equation along the beam and...
A 26.0 ft. simply supported beam is subjected to factored uniformly distributed load of wa equal to 6.0 kips/t. Beam properties are as follows: b-14 in, d-24 in, 4,000 psi (normal-weight concrete) and fy -60,000 psi. Design shear reinforcement for the entire beam (you can use symmetry if applicable). Use two different spacings over the beam length to come up with economical design. Perform all necessary checks and calculations. Draw final design for shear ma reinforcement indicating distribution (i.e, lengths,...
The reinforced concrete beam shown in Figure-2 is to be subjected to the following uniformly distributed loads over the entire length: DL = 14 kn/m (including self-weight) and LL = 20kN/m, fc = 32 MPa. For architectural reasons the beam width is set at 500 mm. Determine the effective depth required if ku = 0.25 for the section of maximum positive bending moment. Then design the reinforcement required. zin Figure-2
The beam having a cross-section as shown is subjected to the distributed load w (1) Calculate the moment of inertia, I (2) If the allowable maximum normal stress ơmax-20 MPa, determine the largest distributed load 5. w. (3) If w 1.5 kN/m, determine the maximum bending stress in the beam. Sketch the stress distribution acting over the cross-section. 100 mm 50mm 120 mm 3 m50 mm 3 m
Q2 The 10 m long simply supported beam is subjected to a uniformly distributed load w = 10 kN/m throughout and a point load P =10 kN at the midspan of the beam, as shown in Figure Q2 (a). The cross section of this beam is depicted in Figure Q2 (b), which consists of three equal rectangular steel members. Self-weight of the beam is neglected. 30 mm P= 10 KN W = 10 kN/m 200 mm 5 m 5 m...
Q2 The 10 m long simply supported beam is subjected to a uniformly distributed load w = 10 kN/m throughout and a point load P =10 kN at the midspan of the beam, as shown in Figure Q2 (a). The cross section of this beam is depicted in Figure Q2 (b), which consists of three equal rectangular steel members. Self-weight of the beam is neglected. 30 mm P = 10 kN W = 10 kN/m 200 mm 5 m 5...
Q2 The 10 m long simply supported beam is subjected to a uniformly distributed load w = 10 kN/m throughout and a point load P =10 kN at the midspan of the beam, as shown in Figure Q2 (a). The cross section of this beam is depicted in Figure Q2 (b), which consists of three equal rectangular steel members. Self-weight of the beam is neglected. 30 mm P = 10 kN w = 10 kN/m 200 mm 5 m 5...
The
Beam shown will be subjected to a concentrated live load of 100kN,
a uniformly distributed live load of 50kN/m and a uniformly
distributed dead load of 20kN/m.
45.) determine the maximum reaction at B
46.) determine the maximum positive shear at C
47.) determine the maximum negative moment at B
The beam shown will be subjected to a concentrated live load of 100 KN, a uniformly distributed live load of 50 kN/m and a uniformly distributed dead load of...
Questions 5-8
A steel frame shown below is subjected to combined uniformly distributed gravity load (w 2 kips/f) and a horizontal earthquake load of H-10 kips Both the beams and the columns are made of W12x120 section having a yield strength of F 45 ksi. The Young's modulus of steel s E-29,000 ksi. The distributed load w is used to simulate the self-weight of the beam, the load transferred from roof slab, as well addition superimposed dead loads. The self-weigh...
The below wooden double overhanging beam is under a uniformly distributed load W. The wood is weak along the orientation of the grain (or wood cell fibres) that makes an angle of 30° with the horizontal (see figure). The maximum shear stress on a plane parallel to the grain that the wood can sustain is t,max = 5 MPa, and the maximum normal stress of wood is omax = 25 MPa. The Young modulus of this wood is E=15 GPa....
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