The rule of ____________ tells us that the probability that an F1 individual with a dominant...
The rule of ____________ tells us that the probability that an F1 individual with a dominant phenotype is a heterozygote is actually ⅔ (since they can not have the recessive genotype).
Homework Answers
The rule of Sum tells us that the probability that an F1 indibidual with a dominant genotype is a heterozygote is actually 2/3.
According to this rule, probability that any mutually exclusive event will occur is equal to sum of individual event probability.
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The rule of ____________ tells us that the probability that an
F1 individual with a dominant...
Observing human phenotypes and probability in genetics Name: _________________________ Purpose Reinforce concepts of simple genetics by...
Observing human phenotypes and probability in genetics Name: _________________________ Purpose Reinforce concepts of simple genetics by examining the following: Genotype Phenotype Homozygous Heterozygous Dominant Recessive Materials Mirror Objectives Determine your phenotype for ten different traits. Determine your possible genotypes for the ten different traits. Evaluate your uniqueness as an individual. Part A- Determining your phenotype and genotype In part “A” you will examine your phenotype, or appearance, and will draw conclusions about your genotype, the gene combinations that determine appearance....
PRE-LAB QUESTIONS - Genetics - Lab #9 1. Humans inherit two alleles for every gene. For...
PRE-LAB QUESTIONS - Genetics - Lab #9 1. Humans inherit two alleles for every gene. For an example, gene "R" provides the instructions for face shape. The dominant allele for the gene is denoted as R and the recessive allele for the gene is denoted as r. The dominant phenotype is a round face shape and the recessive phenotype is a square face shape. Use this information to answer the questions below: What is the genotype of a homozygous dominant...
GENETICS PROBLEMS 1. The gene for widow's peak (W) is dominant to the gene for straight hairline...
GENETICS PROBLEMS 1. The gene for widow's peak (W) is dominant to the gene for straight hairline (w). A male homozygote with widow's peak marries a female homozygote with straight hairline, what are the possible genotypic and phenotypic ratios of the F1 and F2 generations that may result from the union? Phenotype of Parents ………………………… x ………………………… Genotype of Parents ………………………… x ………………………… Genes in gametes ………………………… x ………………………… Genotype of F1 Generation ………………………… Phenotype of F1 Generation ………………………… Genes in F1 gametes ………………………… or ………………………… (Punnett Square)...
a.) Before individual II-2 had an affected son, this family believed the condition followed a dominant...
a.) Before individual II-2 had an affected
son, this family believed the condition followed a dominant mode of
inheritance. Why does the phenotype of III-1 support a
recessive rather than a dominant mode of inheritance?
b.) Could the mode of inheritance actually be dominant? Explain
using appropriate genetic terms.
c.) In order to better understand the risk of passing this
condition on to additional offspring, individual II-2 sought
genetic counseling which resulted in the drawing of this pedigree.
This action makes...
what is the difference between heterozygous and homozygous individuals
What is the difference between heterozygous and homozygous individuals? Homozygotes have one chromosome while heterozygotes have two similar chromosomes. The homozygote will express the dominant trait and the heterozygote will express the recessive trait. All of the gametes from a homozygote carry the same version of the gene while those of a heterozygote will differ. Heterozygotes carry two copies of a gene while homozygotes only carry one. When constructing a Punnett square, the symbols on the outside of the boxes...
When the P generation of true-breeds, are allowed to crossed, the probability that the F1 offspring...
When the P generation of true-breeds, are allowed to crossed, the probability that the F1 offspring will express a homozygous genotype (either recessive or dominant) is: 0% 25% 100% 50%
4. You cross individuals with the following Genotypes, AaBbDdEeFFGg & AaBbDDEeFfGg. Predict the proportion of offspring...
4. You cross individuals with the following Genotypes, AaBbDdEeFFGg & AaBbDDEeFfGg. Predict the proportion of offspring that would show the following Phenotype or Genotype? A) all Dominant Phenotypes, B) the Genotype: AabbDdEeFfgg, C) the Genotype: AABbDdEeFfgg, D) the Genotype: aaBbddEeffGg, & E) all Recessive Phenotypes. 5. You cross individuals with the following Genotypes, AaBbDdEeFFgg x AabbDDEeFfGg. If you produce 1000 offspring in this cross, predict the number of offspring that would have the following Phenotype or Genotype? A) all Dominant...
Can you explain how to do number 4? dominant individual and umail mmetance, hów can one...
Can you explain how to do number 4?
dominant individual and umail mmetance, hów can one differentiaté between a homozygous one who is heterozygous for the dominant trait? (A) By crossing the individuals in question (B) By crossing each individual with a known homozygous recessive and examining the offspring By crossing each individual with a known heterozygote and examining the offspring (C) (D Both B and C If a male hemophiliac (Xhy) is crossed with a female carrier of both...
35. A testcross (backcross) is used to determine: a. an individual has a dominant or recessive...
35. A testcross (backcross) is used to determine: a. an individual has a dominant or recessive phenotype. b flowers are red, pink, or white c. whether an individual is homozygous or heterozygous. d. what types of offspring could be produced 36. If red flower color is dominant over white and a homozygous red flowered plant was crossed with a homozygous white flowered plant, what percentage of their offspring in the Fi generation would have white flowers? a. b. с. 100%...
In zebrafish, the half baked (hab) gene is caused by a mutation in E-cadherin. A new...
In zebrafish, the half baked (hab) gene is caused by a mutation in E-cadherin. A new allele of this gene, k51, has a wild-type phenotype as a heterozygote, and a strong lethal phenotype as a homozygote. However, k51/deletion has a slightly more dramatic phenotype than k51/k51. This test tells us that the new allele is: O a null allele O codominant. O dominant lethal. O temperature sensitive. O haploinsufficient. O a leaky allele O incompletely dominant. O dominant negative. O...
PRE-LAB QUESTIONS - Genetics - Lab #9 1. Humans inherit two alleles for every gene. For an example, gene "R" provides the instructions for face shape. The dominant allele for the gene is denoted as R and the recessive allele for the gene is denoted as r. The dominant phenotype is a round face shape and the recessive phenotype is a square face shape. Use this information to answer the questions below: What is the genotype of a homozygous dominant...
a.) Before individual II-2 had an affected
son, this family believed the condition followed a dominant mode of
inheritance. Why does the phenotype of III-1 support a
recessive rather than a dominant mode of inheritance?
b.) Could the mode of inheritance actually be dominant? Explain
using appropriate genetic terms.
c.) In order to better understand the risk of passing this
condition on to additional offspring, individual II-2 sought
genetic counseling which resulted in the drawing of this pedigree.
This action makes...
What is the difference between heterozygous and homozygous individuals? Homozygotes have one chromosome while heterozygotes have two similar chromosomes. The homozygote will express the dominant trait and the heterozygote will express the recessive trait. All of the gametes from a homozygote carry the same version of the gene while those of a heterozygote will differ. Heterozygotes carry two copies of a gene while homozygotes only carry one. When constructing a Punnett square, the symbols on the outside of the boxes...
Can you explain how to do number 4?
dominant individual and umail mmetance, hów can one differentiaté between a homozygous one who is heterozygous for the dominant trait? (A) By crossing the individuals in question (B) By crossing each individual with a known homozygous recessive and examining the offspring By crossing each individual with a known heterozygote and examining the offspring (C) (D Both B and C If a male hemophiliac (Xhy) is crossed with a female carrier of both...
35. A testcross (backcross) is used to determine: a. an individual has a dominant or recessive phenotype. b flowers are red, pink, or white c. whether an individual is homozygous or heterozygous. d. what types of offspring could be produced 36. If red flower color is dominant over white and a homozygous red flowered plant was crossed with a homozygous white flowered plant, what percentage of their offspring in the Fi generation would have white flowers? a. b. с. 100%...
In zebrafish, the half baked (hab) gene is caused by a mutation in E-cadherin. A new allele of this gene, k51, has a wild-type phenotype as a heterozygote, and a strong lethal phenotype as a homozygote. However, k51/deletion has a slightly more dramatic phenotype than k51/k51. This test tells us that the new allele is: O a null allele O codominant. O dominant lethal. O temperature sensitive. O haploinsufficient. O a leaky allele O incompletely dominant. O dominant negative. O...
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