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PROBLEM 3 The Ericsson Cycle is composed of two isothermal processes and two isobaric processes, with regenerative heat excha

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Ta 3 ५ To = 282.2C = Ty = 55502 R P2 - -689.46 kPa V₂ =142 x 103 m3 Regeneraties V4 V3 2 २ 1 3 Ta = T, = 4.40 = 277.4K assum

First take process a-3 (Isobaric) P₂ = 689.48 kPa Vg = 142 xromo P2 = P2 = 689.48 kPa u = ? T₂ = 55512R Ta= 277.4k Pa V2 Pa

i) Isothermal compression proces To-T R = 287 J/kg-k :: os = 82-8, = R. ln (13) os = 287 ln | 70-95846) .:: OS=-198.93 J/kg-K

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The expression of Efficiency of Ericsson Cycle is same as of carnot cycle.

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