A 1.00 L solution contains 2.0010^-4M Cu(NO3)2 and 1.2010^-3M ethylenediamine (en). The Kf for Cu(en)2 2+...

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A 1.00 L solution contains 2.0010^-4M Cu(NO3)2 and 1.2010^-3M ethylenediamine (en). The Kf for Cu(en)2 2+...

A 1.00 L solution contains 2.00*10^-4M Cu(NO3)2 and 1.20*10^-3M ethylenediamine (en). The Kf for Cu(en)2 2+ is 1*10^20 . What is the concentration of Cu2+ (aq) in the solution.

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Answer 1

Answer #1

The formation constant for Cu(en)₂²⁺ is 1*10²⁰
Cu²⁺ + 2 en -----------> Cu(en)₂²⁺

I (M) : 2.00*10^-4 1.6*10^-3 0

C(M) : -x -2x +x

--------------------------------------------------

E(M) 2.00*10^-4 - x 1.6*10^-3 - 2x x

K_f = [Cu(en)₂²⁺] / [ Cu²⁺][en]²

1*10²⁰ = x (1.6*10^-3 - 2x) / (2.00*10^-4 - x)

x = 5.00*10¹⁹ M

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Answer 2

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