Question

The right-angle bar with equal legs weighs 5.6 lb and is freely hinged to the vertical plate at C. The bar is prevented from rotating by the two pegs A and B foxed to the plate. Determine the acceleration a of the plate for which no force is exerted on the bar by either peg A or B. 8.9" -- 8.9" Answer: - ft/sec Tothly Medis

Answer 1

Answer- acceleration of the plate for which no force is exerted on the bar by either peg A or Peg B= 3*g

Where g= acceleration due to gravity

Details solutions is given below

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Solution Given weight = 5.6db Doan free body 8-52 & call ma diagsam calculate the x-Coordinate the centroid , 8:3+ x(x + 8-3+ = 0 8.9" 8.9t +8.5t J oc 39.605t 2.225 17.8 t Where t= thickness. calcreate y coordinate of the centroid. 8- 9 + 10 + x 31 x 8 ) 8.gt itgigt cal I! ģ = 2:225 of magnitude When the blate accelerates towards right, an inertial force acts at the bars Center of janvity ma towards left Apply the moment equilibrium condition about a condition about a for the sight-angle bat mgě (8.9-50) - maxğ = u Where m = mass of the right-angled bar a= acceleration of the sight angled bar g= gravity due Acco 3. cole

value in ea , Substitute all the Jet X 2:22.5 = x (8.9-24225) (6)xas ( W ) xgx 2.22sa Where -) 6.675 g a = 39 Ang a - Acceleration of the beate ->