Here, the apparent mass of the liquid = 9.9700 – 7.6500 = 2.3200 g.
The same buoyant force acts on the container during both weighing.
Therefore, we need to consider only the force that acts on the 2.3200 g of the liquid.
Now, by substituting, d(air) = 0.0012 g/cm^3
d(obj) = 0.92 g/cm^3
d(wts) = 8.0 g/cm^3
The corrected mass = 2.3200 + 2.3200*(0.0012/0.92 – 0.0012/8.0) = 2.3227 g.
A bottle weighed 7.6500 g empty and 9.9700 g after introduction of an organic liquid with...
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