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Problem 2 Solve the Problem 1 above using Zhmus method...
3.13 A single-line diagram of a three-phase power system is shown in Fig. 3.51. The ratings...
3.13 A single-line diagram of a three-phase power system is shown in Fig. 3.51. The ratings of the equipment are shown below Generator G: 100 MVA, 11 kV, Xi -X2-0.20 pu, Xo -0.05 pu Generator G2 : 100 MVA, 20 kV, Xi=X2=0.25 pu, Xo=0.03 pu, X,,-0.05 pu Transformer T: 100 MVA, 11/66 kV, Xi -X2-Xo 0.06 pu Transformer T2: 100 MVA, 11/66 kV, Xi-X2 = Xo 0.06 pu Line: 100 MVA, X,-X2 = 0.15 pu, Xo = 0.65 pu A...
Power System
A simple three-phase power system is shown in Figure 2. Assume that the ratings of the various devices in this system are as follows: • Generators G1, G2: 40 MVA, 13.2 kV, = 0.15 pu, = 0.15 pu, = 0.08 • Generator G3: 60 MVA, 13.8 kV, = 0.20 pu, 0.20 pu, - 0.08 • Transformers T1, T2, T3, T4: 40 MVA, 13.8/138 kV, X1 = X2 = 0.10 pu, XO 0.08 pu Transformers T5, T6: 30 MVA, 13.8/138 kV, X1 = X2...
A single line diagram of a power system is shown in Fig. 2. The system data with equipment ratings and assumed sequence reactances are given the following table. The neutrals of the generator and A-Y...
A single line diagram of a power system is shown in Fig. 2. The system data with equipment ratings and assumed sequence reactances are given the following table. The neutrals of the generator and A-Y transformers are solidly grounded. The motor neutral is grounded through a reactance Xn 0.05 per unit on the motor base. Assume that Pre-fault voltage is takin as VF-1.0 ,0° per unit and Pre- fault load current and Δ-Y transformer phase shift are neglected In the...
Question 4 The power system shown is supplying a balanced wye-grounded resistive load that consumes the...
Question 4 The power system shown is supplying a balanced wye-grounded resistive load that consumes the MW at 1.1 kV. An SLG fault occurs at bus 3. Determine the fault current and the voltages at the fault point. Assume that the fault resistance is 6.6 2. The equipment parameters are shown in the figure. 3 4 2 (1 (1 + j5) 2 10 MW Tuto 20 MVA 22/1.1 kV X = X2 = Xo = 0.05 pu Generator 30 MVA...
Problem 2 (50 points): The generator in the figure generates and delivers 150 MW to the...
Problem 2 (50 points): The generator in the figure generates and delivers 150 MW to the power system below. At steady state the generator regulates the generating station voltage (bus 1) to pu. The system voltage at bus 3 is 1.05 pu. 1. Compute the internal voltage and rotor angle of the generator under the above conditions. 2. The fault sequence for a solid three-phase fault on any of the line circuits consists of a delayed tripping of both circuit...
The component parameters for the power system shown in Figure 2 are given in Table 1. The pre-fau...
The component parameters for the power system shown in Figure 2 are given in Table 1. The pre-fault voltage is 120° pu and Zx-j0.1 pu. Table 1 Ratings X2-Xi (pu)Xo (pu) 0.05 0.10 0.20 0.20 Components G1, G2 200 MVA, 20 kV 0.10 0.10 0.10 0.10 T1, T2, T3200 MVA, 20/200 kV L1 200 MVA, 200 kV し2 200 MVA, 20 kV (a) Draw the three sequence networks and determine the per-unit Thevenin impedance of each sequence network seen from...
can you calculating this question and explain why? thanks The ratings and sequence reactances of the components for...
can you calculating this question and explain why?
thanks
The ratings and sequence reactances of the components for the power system shown in Figure 2 are given in Table 1. The pre-fault voltage is 1/0° per unit (pu). Bus 8 L3 Bus 1 T1 Bus 4 T2 Bus 2 Bus 5 L1 L2 G1 Bus 3 T3 Bus 7 Bus 6 D.6975 Figure Draw the per unit impedance sequence networks and determine the per unit (a) Thevenin impedances of the...
PLEASE SOLVE THIS POWER / LOAD FLOW 07-Elec-B December 2016 Page 7 of 7 Problem 7...
PLEASE SOLVE THIS POWER / LOAD FLOW
07-Elec-B December 2016 Page 7 of 7 Problem 7 Consider the system shown in the single-line diagram of Figure (5). Here, a 60-Hz synchronous generator having a transient reactance of 0.15 pu. is connected to an infinite bus through a transformer whose reactance is 0.1 p. u. and a double circuit transmission line with circuits having a reactance of 0.6 p.u each as indicated in the figurc. The generator delivers a real power...
Q3: (15 Points) Equi below are given as follows: pment ratings and per-unit reactances for the sy...
Q3: (15 Points) Equi below are given as follows: pment ratings and per-unit reactances for the system shown in circuit 2 4 T1 TL12 T2b G1 G2 TL13 TL23 0.03 j0.03 Synchronous Generators: G1 100 MVA 25 kV G2 100 MVA 3.8 kV Transformers: T1 100 MVA 25/230 kV T2 100 MVA 13.8 /230 kV X1=X2= 0.2 X0-0.05 X1-X2-0.2 X0 0.05 X1 = X2-X0 = 0.05 Transmission lines: TL12 100 MVA TL13 100 MVA TL23 100 MVA X0 0.3 XO...
The one-line diagram of a simple power system is shown in Figure 1. The neutral of...
The one-line diagram of a simple power system is shown in Figure 1. The neutral of each generator is grounded through a current-limiting reactor of 0.25/3 per unit on a 100-MVA base. The system data expressed in per unit on a common 100-MVA base is tabulated below. The generators are running on no-load at their rated voltage and rated frequency with their emfs in phase. Determine the fault current for the following faults giving Zo = 0.35, Z = 0.22...
3.13 A single-line diagram of a three-phase power system is shown in Fig. 3.51. The ratings of the equipment are shown below Generator G: 100 MVA, 11 kV, Xi -X2-0.20 pu, Xo -0.05 pu Generator G2 : 100 MVA, 20 kV, Xi=X2=0.25 pu, Xo=0.03 pu, X,,-0.05 pu Transformer T: 100 MVA, 11/66 kV, Xi -X2-Xo 0.06 pu Transformer T2: 100 MVA, 11/66 kV, Xi-X2 = Xo 0.06 pu Line: 100 MVA, X,-X2 = 0.15 pu, Xo = 0.65 pu A...
A single line diagram of a power system is shown in Fig. 2. The system data with equipment ratings and assumed sequence reactances are given the following table. The neutrals of the generator and A-Y transformers are solidly grounded. The motor neutral is grounded through a reactance Xn 0.05 per unit on the motor base. Assume that Pre-fault voltage is takin as VF-1.0 ,0° per unit and Pre- fault load current and Δ-Y transformer phase shift are neglected In the...
Question 4 The power system shown is supplying a balanced wye-grounded resistive load that consumes the MW at 1.1 kV. An SLG fault occurs at bus 3. Determine the fault current and the voltages at the fault point. Assume that the fault resistance is 6.6 2. The equipment parameters are shown in the figure. 3 4 2 (1 (1 + j5) 2 10 MW Tuto 20 MVA 22/1.1 kV X = X2 = Xo = 0.05 pu Generator 30 MVA...
Problem 2 (50 points): The generator in the figure generates and delivers 150 MW to the power system below. At steady state the generator regulates the generating station voltage (bus 1) to pu. The system voltage at bus 3 is 1.05 pu. 1. Compute the internal voltage and rotor angle of the generator under the above conditions. 2. The fault sequence for a solid three-phase fault on any of the line circuits consists of a delayed tripping of both circuit...
The component parameters for the power system shown in Figure 2 are given in Table 1. The pre-fault voltage is 120° pu and Zx-j0.1 pu. Table 1 Ratings X2-Xi (pu)Xo (pu) 0.05 0.10 0.20 0.20 Components G1, G2 200 MVA, 20 kV 0.10 0.10 0.10 0.10 T1, T2, T3200 MVA, 20/200 kV L1 200 MVA, 200 kV し2 200 MVA, 20 kV (a) Draw the three sequence networks and determine the per-unit Thevenin impedance of each sequence network seen from...
can you calculating this question and explain why?
thanks
The ratings and sequence reactances of the components for the power system shown in Figure 2 are given in Table 1. The pre-fault voltage is 1/0° per unit (pu). Bus 8 L3 Bus 1 T1 Bus 4 T2 Bus 2 Bus 5 L1 L2 G1 Bus 3 T3 Bus 7 Bus 6 D.6975 Figure Draw the per unit impedance sequence networks and determine the per unit (a) Thevenin impedances of the...
PLEASE SOLVE THIS POWER / LOAD FLOW
07-Elec-B December 2016 Page 7 of 7 Problem 7 Consider the system shown in the single-line diagram of Figure (5). Here, a 60-Hz synchronous generator having a transient reactance of 0.15 pu. is connected to an infinite bus through a transformer whose reactance is 0.1 p. u. and a double circuit transmission line with circuits having a reactance of 0.6 p.u each as indicated in the figurc. The generator delivers a real power...
Q3: (15 Points) Equi below are given as follows: pment ratings and per-unit reactances for the system shown in circuit 2 4 T1 TL12 T2b G1 G2 TL13 TL23 0.03 j0.03 Synchronous Generators: G1 100 MVA 25 kV G2 100 MVA 3.8 kV Transformers: T1 100 MVA 25/230 kV T2 100 MVA 13.8 /230 kV X1=X2= 0.2 X0-0.05 X1-X2-0.2 X0 0.05 X1 = X2-X0 = 0.05 Transmission lines: TL12 100 MVA TL13 100 MVA TL23 100 MVA X0 0.3 XO...
The one-line diagram of a simple power system is shown in Figure 1. The neutral of each generator is grounded through a current-limiting reactor of 0.25/3 per unit on a 100-MVA base. The system data expressed in per unit on a common 100-MVA base is tabulated below. The generators are running on no-load at their rated voltage and rated frequency with their emfs in phase. Determine the fault current for the following faults giving Zo = 0.35, Z = 0.22...
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