Fatty acids are long chain aliphatic hydrocarbons with carboxylic acid functional group. They can be classified into saturated or unsaturated fatty acids. The carbon chain in fatty acids starts from 5 carbons to 22 carbon atoms.
Saturated fatty acid: The long chain hydrocarbon contains only single bond. There is no double or triple bonds present in the structure.
Unsaturated fatty acid: The long chain hydrocarbon contains double and triple bonds.
The fatty acid (long chain hydrocarbon) can be represented in a ratio format.
Example: 15:3
The ratio 15:3 represents that the fatty acid should contain total number of 15 carbons and 3 represents the structure that contain 3 double bonds.
The carbon skeleton is drawn below.
Fatty acid:
Ans:
Modify the following fatty acid so that it represents the 18-carbon fatty acid designated 18:2(?9,12). Draw...
Modify the given fatty acid so that it represents the 18-carbon fatty acid designated 18:2( A the cis configuration. Utlizise Groups when appropriate. 2). Draw any double bonds in Select Draw Rings Groups More Erase
Modify the given fatty acid so that it represents the 18-carbon fatty acid designated 18:21A%.12). Draw any double bonds ir the cis configuration. Utlizise Groups when appropriate. Select Draw Rings Groups More mm
Modify this 18-carbon fatty acid so that it becomes an omega-3 (?–3) fatty acid designated as 18:3. Draw the double bonds in the cis configuration. Modify this 18-carbon fatty acid so that it becomes an omega-3 (-3) fatty acid designated as 18:3. Draw the double bonds in the cis configuration. COO
drawing and explanation please Modify the given fatty acid so that it represents the 18-carbon fatty acil designated 18:2(A912). Draw any double bonds in the cis configuration. Utlizise Groups when appropriate. Select Draw Rings Groups More Erase COOH COO COO
Modify this 18-carbon fatty acid so that it becomes an omega-3 (0-3) fatty acid designated as 18:3. Draw the double bonds in the cis configuration. Select Draw Rings More Erase 2
drawing and explanation please Modify this 18-carbon fatty acid so that it becomes an omega-6 (o-6) fatty acid designated as 18:2. Add a double bond that is in the cis configuration. Erase Select Draw Rings More H
5) (3 pts) Draw an essential -6 fatty acid with 18 carbons and two cis double bonds. Number carbon atoms in this fatty acid starting at the carboxyl group. 6) (3 pts) Draw an essential 0-3 fatty acid with 18 carbons and three cis-double bonds. Number carbon atoms in this fatty acid starting at the carboxyl group. 7) (3 pts) Draw an unnatural trans-fatty acid arising from partial hydrogenation that contains 14 carbons and two double bonds, one of which...
Assignment Score: 100/300 Resources Hint Check Answer Check Answer < Question 1 of 3 > Modify the given fatty acid so that it represents the 18-carbon fatty acid designated 18:2(A%.12). Draw any double bonds in the cis configuration. Utlizise Groups when appropriate. Select Draw Rings Groups More Erase COO-
Which of the following explanations describes the fatty acid with the highest melting point: 18 carbons long, 2 double bonds, both in the cis configuration 18 carbons long and saturated 18 carbons long, 1 double bond, cis configuration 18 carbons long, 1 double bond, trans configuration
4. Calculate the results of the catabolism of linoleic acid, an 18-carbon fatty acid containing 2 carbon-carbon double bonds. Show your calculation to get credit. TOTAL NADH formed: ______ TOTAL FADH2 formed: - TOTAL GTP formed: --