Question

e) Calculate the cost of implementing Cout and the cost of implementing the Sum in the following circuit: Cost of implementing Cout = Cost of implementing Sum =

Answer 1

cout t o 496+A=A+B)à SÃO КАВА D Don A+B+B = (A+ D BA W. AB + B A+ Cina (ABABA) Cin = ÃBE in this cin x= within a on KE AB ISA +Cin't cine (AbhAtein)..in antin Y= ĀBTSA TN = ADA ADIBATW sum = x+y = ĀDI SA tw tit cin =(AB + B A tw) (within)=(As. Ja tw.) (wt Cin) sum =((A+6) (64) +w) (we cin) = (AB+ ĀB+w) (0+ Cin) sum= ABW tñontwt AB (in tãieint W cin Suna A B cit A B Cinta Beint Ā B Cine gcout A+B tw - (A+B Jw z(A+B)(B+BA+cin) -(A+B) (AGA + Cin) =(4+0) (A+2.) (6+Atsin) cout = (P+6) CABA t à à t cin) = AB + Acint AB + 2 +B (in = ABt Blint "in A.

"sum = = AB Sint AB ĀBin in Ain T ARCín + cout = AB + BC + (in A. of soon logic equation is cost (F): Nor of literals + No, of termes + - No, of complement literals. cost (som) - S e 6+ 4+ 3 = 13 sum cost ca C - Out 3+3+0 -6 © 22 '+ B'c' 2: HB (etc'Do +(A+A!) a'd' (D40') 2 = A'BCD ta'bc'o +(AB'e't Alf'c') (0+0') 2 - ABCgt AB co + AB'C'z ta'sidst Ab'c'otárs'c's! mq mas ma m, ma mo Olot 100 0001 1010000 2= Em (0,1,5,7,9) = .mtm, tmg + m₂ +ma Os Q Q, Q. TOD Q3 = Q,= 0011 4:03= Q3 Q, o Q - Q,-0