which critical value is appropriate for a 99% confidence level where n = 17. is unknown,...
Which critical value is appropriate for a 99% confidence level where nequals=17, sigmaσ is unknown, and the population appears to be normally distributed? A. z Subscript alpha divided by 2zα/2equals=2.583 B. t Subscript alpha divided by 2tα/2equals=2.898 C. z Subscript alpha divided by 2zα/2equals=2.567 D. t Subscript alpha divided by 2tα/2equals=2.921
(l point) 9. You are constructing a 90% confidence interval for a sample consisting of n-9 values and an unknown population standard deviation. The population appears to be very skewed. Determine whether a margin of error should be calculated using a critical value of zan, a critical value of a2, or neither a critical value of a 2 a critical value of ta2 O neither 10. A simple random sample has a sample size of n - 65. Given the...
11. Do one of the following, as appropriate: (a) Find the critical value z a, (b) find the critical value (ipoint tap, (c) state that neither the normal nor the t distribution applies. 99%; n = 17, σ is unknown; population appears to be normally distributed. O zan 2.583 O tan a/2 -2.898 O ta/2-2921 O za/2#2567 12. Do one of the following, as appropriate: (a) Find the critical value za/2, (b) find the critical value (point) tan,(c) state that...
Find the appropriate critical value either 20 ) Confidence level = 99% and =21 012-2901 022=2567 012-2845 0292=253 012=2898 O None of these
fins the critical value ta/2 that corresponds to 99% confidence level for a sample size n=15
Find the critical value tc for the confidence level c=0.98 and sample size n=17. Round to nearest thousands Find the critical value tc for the confidence level c=0.99 sample size n=9. Round to nearest thousandth.
To construct a 99% confidence interval where o is known, the correct critical value is 1.96. True or false
Use the standard normal distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justify your decision. If neither distribution can be used, explain why. Interpret the results. In a recent season, the population standard deviation of the yards per carry for all running backs was 122. The yards per carry of 25 randomly selected running backs are shown below. Assume the yards per carry are normally distributed 22 2.9 3.9 4.6 5.5 5.5 62 75...
Use the standard normal distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justify your decision. If neither distribution can be used, explain why. Interpret the results. In a recent season, the population standard deviation of the yards per carry for all running backs was 1.21. The yards per carry of 25 randomly selected running backs are shown below. Assume the yards per carry are normally distributed. 3.2 6.8 6.1 3.6 6.3 7.1 6.4 5.5...
(i point) 6. Give a correct interpretation of a 99% confidence level of 0 102 <p < 0 236, alue of the population proportio We are 99% confident that the interval from 0 102 to 0.236 actually does contain the tru O There is a 99% chance that the true value ofp will fall between 0 i 02 and 0236. 99% of sample proportions fall between 0 102 and 0 236 o we are confident that 99% of values between...