fins the critical value ta/2 that corresponds to 99% confidence level for a sample size n=15
Solution :
At 99% confidence level the t is ,
= 1 - 99% = 1 - 0.99 = 0.01
/ 2 = 0.01 / 2 = 0.005
n = 15
df = 15 - 1 = 14
t 0.005,14 = 2.977
fins the critical value ta/2 that corresponds to 99% confidence level for a sample size n=15
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For a confidence level of 99% with a sample size of 29, find the critical t value. Points possible: 1 Unlimited attempts. Score on last attempt: 0. Score in gradebook: 0 Message instructor about this question Submit
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