Question

A rod is to be used in an aerospace application. The defense contractor has mandated a factor of safety of 2.6. In its application, the maximum tensile axial load on the rod ranges from       = 2.1 kN to 2.8 kN. The metal alloy that the rod is made of has a tensile yield strength of 480 MPa and an ultimate strength of 560 MPa. The specification for the radius of the rod is given on the drawing.

If the rod exceeds its elastic limit, the part will fail.

| 250.200+0.02.cn R=0.200+0.022 cm

Determine whether the rod as described will meet the

specifications through calculations. If it does not meet the factor

of safety, describe two ways that it could be brought into spec to

satisfy the defense contractor.

Answer 1

Fos = 206. s vibn Y Tyt = 480 MPa - yield trength intention to Gut = 560 mpg - ultimate 'strerythintenson, Assuming Constant load whose rarge is 20lk to soft . Rod should not exceed elastic limit so use yield Strength to win calculating the new radius of god for maxm lood of 28kN z Prnax Are you > A? 2.6270° > A94 mma 480 2 xr2=91 mm2 & 2.197 mm rz 0-2197 cm Given radius = 0.200 + 0.022cm Romax = 0.222cm > 0.2197cm but Rmin = 0.2000 - 0.022 = 0.178 cm to we need correction and they may beini Deither use a little higher radius rod use a material with higher value of byt d. or CS scann e CS Scannedgwith Cảmscanner r