A 25.00 mL metal solution containing 0.025M Cu+, 0.050M Ag+, and 0.045M Pb²+ is titrated with 0.05000 M ETDA @ pH = 7
12. A 25.00 mL metal solution containing 0.025M Cu+, 0.050M Ag+, and 0.045M Pb²+ is titrated with 0.05000 M ETDA @ pH = 7. What is the equivalence volume of EDTA?
13. Which metal from question 12 binds strongest to EDTA at pH = 7?
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A 25.00 mL metal solution containing 0.025M Cu+, 0.050M Ag+, and 0.045M Pb²+ is titrated with 0.05000 M ETDA @ pH = 7
A 1.000-mL aliquot of a solution containing Cu and Ni2 is treated with 25.00 mL of...
A 1.000-mL aliquot of a solution containing Cu and Ni2 is treated with 25.00 mL of a 0.05182 MEDTA solution. The solution is then back titrated with 0.02198 M Zn2 solution at a pH of 5. A volume of 21.82 mL of the Zn2 solution was needed to reach the xylenol orange end point. A 2.000-mL aliquot of the Cu and Ni2 solution is fed through an ion-exchange column that retains Ni2. The Cu2 that passed through the column is...
A solution containing 10.00 mL of 0.0500 M metal ion buffered to pH = 10.00 was...
A solution containing 10.00 mL of 0.0500 M metal ion buffered to pH = 10.00 was titrated with 0.0400 M EDTA. Answer the following questions and enter your results with numerical value only. Calculate the equivalence volume, Ve, in milliliters. Calculate the concentration (M) of free metal ion at V = 1/2 Ve. If the formation constant (Kf) is 1012.00. Calculate the value of the conditional formation constant Kf’ (=αY4- * Kf) and enter your result as scientific notation form....
A 1.000-mL aliquot of a solution containing Cu2* and Ni2+ is treated with 25.00 mL of...
A 1.000-mL aliquot of a solution containing Cu2* and Ni2+ is treated with 25.00 mL of a 0.04152 M EDTA solution. The solution is then back titrated with 0.02204 M Zn2 solution at a pH of 5. A volume of 16.29 mL of the Zn2+ solution was needed to reach the xylenol orange end point. A 2.000-mL aliquot of the Cu2 and N solution is fed through an ion-exchange column that retains NP. The Cu2" that passed through the column...
A 1.000-mL aliquot of a solution containing Cu2 and Ni2 is treated with 25.00 mL of...
A 1.000-mL aliquot of a solution containing Cu2 and Ni2 is treated with 25.00 mL of a 0.04328 M EDTA solution. The solution is then back titrated with 0.02246 M Zn2 solution at a pH of 5. A volume of 21.60 mL of the Zn2 solution was needed to reach the xylenol orange end point. A 2.000-mL aliquot of the Cu2 and Ni2 solution is fed through an ion-exchange column that retains Ni2 . The Cu2 that passed through the...
10.6 10.00 mL of a sample of a solution containing Feand Co are added to 100...
10.6 10.00 mL of a sample of a solution containing Feand Co are added to 100 mL of pH 4.5 buffer and then titrated to a Cu-PAN endpoint with 18.82 mL of 0.05106 M EDTA. Then, 25.00 mL of the same of the same solution are added to 100 mL of pH 4.5 buffer along with 10 mL of 1 M potassium fluoride, which is added to mask the Fe'. This solution was titrated to a Cu-PAN endpoint with 13.40...
3. A 25.00 mL 0.0250 M calcium carbonate sample is titrated with 14.3 mM EDTA solution....
3. A 25.00 mL 0.0250 M calcium carbonate sample is titrated with 14.3 mM EDTA solution. Both sample and titrant are buffered at pH = 10.0 a. What is the titration reaction and what is the value of the conditional formation constant? b. What is the calcium ion concentration when 12.35 mL of titrant has been added? c. What is pCa2+ at the equivalence volume?
The metal ion Mn+ was titrated with 0.0500 M EDTA. The initial solution contained 100.0 mL...
The metal ion Mn+ was titrated with 0.0500 M EDTA. The initial solution contained 100.0 mL of 0.0500 M metal ion (Mn+) buffered at a pH of 9.00. a) Calculate the equivalence volume (Veq). b) What is the concentration of the free metal ion at volume V = Veq/2. c) If the conditional formation constant, K’f = 5.4 X 1010, calculate the concentration of free metal ion at volume V = Veq.
23. A 25.00 mL water sample is titrated with a 0.0120 M EDTA solution. The equivalence...
23. A 25.00 mL water sample is titrated with a 0.0120 M EDTA solution. The equivalence point is reached when 17.0 mL of the EDTA is added. The hardness in the sample was ppm CаCОз. a) 817 b) 219 c) 120 d) 346 e) none of the above
A 25.00 mL solution of 0.08610 M Nal is titrated with 0.05000 M AgNO . Calculate...
A 25.00 mL solution of 0.08610 M Nal is titrated with 0.05000 M AgNO . Calculate pAg+ following the addition of the given volumes of AgNO,. The Ksp of Agl is 8.3 x 10-'7. 37.40 mL pAgt = V pAgt = 47.90 mL pAgt =
A 25.00 mL solution containing 0.035 M sodium acetate is titrated with a 0.098 M solution...
A 25.00 mL solution containing 0.035 M sodium acetate is titrated with a 0.098 M solution of HCl. How many milliliters of HCI are required to reach the endpoint? Answer CHECK A 25.00 mL solution containing 0.035 M sodium acetate is titrated with a 0.098 M solution of HCI. How many milliliters of HCI are required to reach the endpoint? Answer: CHECK
A 1.000-mL aliquot of a solution containing Cu and Ni2 is treated with 25.00 mL of a 0.05182 MEDTA solution. The solution is then back titrated with 0.02198 M Zn2 solution at a pH of 5. A volume of 21.82 mL of the Zn2 solution was needed to reach the xylenol orange end point. A 2.000-mL aliquot of the Cu and Ni2 solution is fed through an ion-exchange column that retains Ni2. The Cu2 that passed through the column is...
A 1.000-mL aliquot of a solution containing Cu2* and Ni2+ is treated with 25.00 mL of a 0.04152 M EDTA solution. The solution is then back titrated with 0.02204 M Zn2 solution at a pH of 5. A volume of 16.29 mL of the Zn2+ solution was needed to reach the xylenol orange end point. A 2.000-mL aliquot of the Cu2 and N solution is fed through an ion-exchange column that retains NP. The Cu2" that passed through the column...
10.6 10.00 mL of a sample of a solution containing Feand Co are added to 100 mL of pH 4.5 buffer and then titrated to a Cu-PAN endpoint with 18.82 mL of 0.05106 M EDTA. Then, 25.00 mL of the same of the same solution are added to 100 mL of pH 4.5 buffer along with 10 mL of 1 M potassium fluoride, which is added to mask the Fe'. This solution was titrated to a Cu-PAN endpoint with 13.40...
23. A 25.00 mL water sample is titrated with a 0.0120 M EDTA solution. The equivalence point is reached when 17.0 mL of the EDTA is added. The hardness in the sample was ppm CаCОз. a) 817 b) 219 c) 120 d) 346 e) none of the above
A 25.00 mL solution of 0.08610 M Nal is titrated with 0.05000 M AgNO . Calculate pAg+ following the addition of the given volumes of AgNO,. The Ksp of Agl is 8.3 x 10-'7. 37.40 mL pAgt = V pAgt = 47.90 mL pAgt =
A 25.00 mL solution containing 0.035 M sodium acetate is titrated with a 0.098 M solution of HCl. How many milliliters of HCI are required to reach the endpoint? Answer CHECK A 25.00 mL solution containing 0.035 M sodium acetate is titrated with a 0.098 M solution of HCI. How many milliliters of HCI are required to reach the endpoint? Answer: CHECK
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