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A 10 mL volume of a 5 mM lactic acid solution is mixed with 5 mL...

A 10 mL volume of a 5 mM lactic acid solution is mixed with 5 mL of water. What is the concentration of the resulting mixture in

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Answer #1

To calculate this problem, consider the serial dilution formula: Molarity (start) x Volume (start) = Molarity (final) x Volume (final) or M1V1 = M2V2.

  • M1= 5mM
  • M2= ?
  • V1= 10
  • V2= 15 ml

Thus, 5×10 = ?× 15 = 3.3 mM

Convert the millmolar into micromolar gives 3300 µM, hence the concentration of the resulting mixture is 3.3 ×103 µM.

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Answer #2

Given:

Volume of lactic acid, V = 10ml

molarity, M= 5mM

converting mM to

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