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A certain sports team wins 0.55% of the time when they play in their home city, but only wins 0.49% when they play in another

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Answer #1

Different relationships between probabilities corresponding to this type of problem are as follows.

Thus in particular for the given example of discussion, we observe that probability of win is calculated after conditioning over two different events namely 'home' and 'away'. Sum of these two may be lesser than 1, equal to 1 or greater than 1. In other words, there is no exact relation between these two probabilities.

Hence, B. P(win| away) and P(win| home) are not required to sum to one since they're conditioned on different events.

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