A 2.08-kg particle has a velocity (2.09 î − 3.07 ĵ) m/s, and a 3.09-kg particle has a velocity (1.03 î + 5.97 ĵ) m/s.
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A 1.96-kg particle has a velocity (2.08 î − 3.07 ĵ) m/s, and a 3.05-kg particle has a velocity (1.08 î + 5.96 ĵ) m/s. (a) Find the velocity of the center of mass. (b) Find the total momentum of the system.
A 1.30-kg particle moves in the xy plane with a velocity of = (4.10 î − 3.80 ĵ) m/s. Determine the angular momentum of the particle about the origin when its position vector is = (1.50 î + 2.20 ĵ) m.
A particle initially located at the origin has an initial velocity of vi = 30.0 î m/s + 50.0 ĵ m/s. If the velocity of the particle at t = 5.0 s is v = 12.0 î m/s + 60.0 ĵ m/s, what is the particle's acceleration (in m/s2)? (Express your answer in vector form.)
A particle initially located at the origin has an acceleration of vector a = 2.00ĵ m/s2 and an initial velocity of vector v i = 6.00î m/s. (a) Find the vector position of the particle at any time t (where t is measured in seconds). ( t î + t2 ĵ) m (b) Find the velocity of the particle at any time t. ( î + t ĵ) m/s (c) Find the coordinates of the particle at t = 3.00...
A particle initially located at the origin has an acceleration of vector a = 4.00ĵ m/s2 and an initial velocity of vector v i = 9.00î m/s. (a) Find the vector position of the particle at any time t (where t is measured in seconds). ( t î + t2 ĵ) m (b) Find the velocity of the particle at any time t. ( î + t ĵ) m/s (c) Find the coordinates of the particle at t = 9.00...
A 2.80-kg object has a velocity (6.20 î - 2.40 ĵ) m/s. (Note: From the definition of the dot product, v2 = v with arrow · v with arrow.) (a) What is its kinetic energy at this moment? (b) Find the net work done on the object if its velocity changes to (8.00 î+ 4.00 ĵ) m/s. J
An object of mass 2.91 kg, moving with an initial velocity of 4.99 î m/s, collides with and sticks to an object of mass 2.36 kg with an initial velocity of -3.19 ĵ m/s. Find the final velocity of the composite object.
A proton moves through a region containing a uniform electric field given by = 30.0 ĵ V/m and a uniform magnetic field = (0.200 î + 0.300 ĵ + 0.400 ) T. Determine the acceleration of the proton when it has a velocity = 230 î m/s. could you also explain in detail the vector addition process?
The vector position of a particle varies in time according to the expression r with arrow = 7.40 î − 5.00t2 ĵ where r with arrow is in meters and t is in seconds. (a) Find an expression for the velocity of the particle as a function of time. (Use any variable or symbol stated above as necessary.) v with arrow = m/s (b) Determine the acceleration of the particle as a function of time. (Use any variable or symbol...
The position vector of a particle of mass 2.10 kg as a function of time is given by r with arrow = (6.00 î + 5.80 t ĵ), where r with arrow is in meters and t is in seconds. Determine the angular momentum of the particle about the origin as a function of time. k kg · m2/s 6.00 і + 5.80 tj. where r ıs in meters and t is in seconds. Determine the angular momentum of the...