Homework Answers
Add Answer to:
Given the data table below develop the precedence network and perform the CPM calculations. Then, using...
Question 1: I)-What is the normal cost of this project? II)-What is the cost of the...
Question 1:
I)-What is the normal cost of this project?
II)-What is the cost of the project after 2 days shortening?
III)-What is the crashing cost per day for activity G?
Given the following data and network, find answer the questions 18-20 if you're asked to finish this project 2 days earlier than its normal duration. Indirect cost (overhead) is $200 per day. 9.12 E 3 1.8 12. 19 10,13 B 7 1,8 13.20 0,1 1,7 8.15 20,25 15.20 F...
Given the following data and network, find answer the questions 18-20 if you're asked to finish...
Given the following data and network, find answer the questions 18-20 if you're asked to finish this project 2 days earlier than its normal duration. Indirect cost (overhead) is $200 per day. 9.12 1.8 E 3 12. 19 B 10.13 H 7 1.8 13.20 0.1 1.7 8.15 15.20 20.25 A F I с 6 u K 5 20.25 0.1 8.15 15.20 4. 12 2.8 1.4 D 3 6,9 15.18 G 8 9.17 3 17.20 Duration Normal Crash Days Shortened 7...
what is the normal cost of this project? what is the cost of the project after...
what is the normal cost of this project?
what is the cost of the project after 2 days shortening?
what is the crashing cost per day for avtivity G?
Given the following data and network, find answer the questions 18-20 if you're asked to finish this project 2 days earlier than its normal duration. Indirect cost (overhead) is $200 per day. 9.12 E 1.8 اليا 12.19 10.13 B 7 H 7 1.8 13, 20 0.1 1.7 8.15 20,25 15, 20...
Question 2. (30%) The following table provides the information necessary to construct project network and calculate...
Question 2. (30%) The following table provides the information necessary to construct project network and calculate a total project cost. In case of activity crash, the information includes crash cost for each activity. Activity Immediate predecessor(s) Activity time (weeks) Normal cost (x1000$) Additional cost for crashing one week (x1000$) Normal After maximum crash A - 16 12 2,000 300 B - 14 9 1,000 160 C A 8 6 500 100 D A 5 4 600 700 E B 4...
Forecasting method
Use the moving average method to forecast period 105.Use the exponential smoothing method to forecast period 105.Use the time-series decomposition method to forecast period 105.Comparing the three methods, which one fits this situation best?The larger the parameter (n) is set, the more historical data are taken into account by the moving average.You can choose different parameter (n) to extrapolate to compare the prediction effect.In general, the parameter (n) should not be taken too large.Moving average.153025703560453055106560761085609580106101165012700136701470015760167301776018820197802090021840227702382024800257602676027770287902976030740317203267033690344703567036690376203865039610406204164042590436104460045630466004763048640496105059051610526305366054640558105679057820586505971060700616706269063730647306576066790678106887069890708707189072880739307498075900768607789078880798708084081860829108387084860858408654087780887508978090760917109273093750947509571096750977209877099740100750101760102780103800104850105Exponential smoothingsame153025703560453055106560761085609580106101165012700136701470015760167301776018820197802090021840227702382024800257602676027770287902976030740317203267033690344703567036690376203865039610406204164042590436104460045630466004763048640496105059051610526305366054640558105679057820586505971060700616706269063730647306576066790678106887069890708707189072880739307498075900768607789078880798708084081860829108387084860858408654087780887508978090760917109273093750947509571096750977209877099740100750101760102780103800104850105Time-series decomposition153025703560453055106560761085609580106101165012700136701470015760167301776018820197802090021840227702382024800257602676027770287902976030740317203267033690344703567036690376203865039610406204164042590436104460045630466004763048640496105059051610526305366054640558105679057820586505971060700616706269063730647306576066790678106887069890708707189072880739307498075900768607789078880798708084081860829108387084860858408654087780887508978090760917109273093750947509571096750977209877099740100750101760102780103800104850105
Given below is the crashing data for a project along with other data. The project completion...
Given below is the crashing data for a project along with other data. The project completion time is 20 davs. Determine: (a) the crash slope (i.e crash cost/day) for all activities, (b) the normal total project cost, (c) prioritized the list of activities for crashing from best to worst, (d) the best activity to crash if the project has to be completed in 19 days and alternative critical paths, if any, (e) the earliest time the project can be completed,...
The Advanced Tech Company has a project to design an integrated information data base for a major bank. Data for the pr...
The Advanced Tech Company has a project to design an integrated information data base for a major bank. Data for the project are given $150 per day. The company will incur a $100 per day penalty for each day the project lasts beyond day 15. the following table. Indirect project costs amount to Normal Time Crash Time Crash Cost Immediate Normal Cost (S) Activity Predecessor(s) (S) (days) (days) 1.200 A 6 800 4 6 1,000 2 2,200 600 900 C...
Next SIX questions are related to the following data: The following is a random sample of...
Next SIX questions are related to the following data: The following is a random sample of n = 90 undergraduate students' annual textbook expense. 610 600 300 420 520 470 430 520 400 370 730 480 450 500 650 370 540 330 690 550 450 450 750 750 660 700 300 770 760 390 680 450 590 630 530 700 580 390 330 320 350 490 310 320 780 590 370 470 760 550 630 450 640 620 520 440...
Below are the data for a Time-Cost CPM Scheduling model analysis. The time is in days....
Below are the data for a Time-Cost CPM Scheduling model analysis. The time is in days. Activity Immediate Predecessor Normal Time Crash Time Normal Cost Crash Cost A None 4 3 202 383 B A 5 3 303 601 C A 1 1 190 285 D B and C 5 4 509 543 E D 4 2 502 898 What is the total time of this project? Please give your answer in days What are the total normal cost of...
Data on small maintenance project is given as below: Depend Time Normal Crash Activity on Cost Time Cost 6 days $70...
Data on small maintenance project is given as below: Depend Time Normal Crash Activity on Cost Time Cost 6 days $700 4 days$800 4 days400 5 days 8 days 10 days 200 7 days 3 days600 6 days50 650 625 7 days 250 700 600 s 400 425 days 3 days 500 On completion, the project will give a return of S110day. Using time-cost trade-off method, how much would you like to compress the project for maximiz ng the return?...
Question 1:
I)-What is the normal cost of this project?
II)-What is the cost of the project after 2 days shortening?
III)-What is the crashing cost per day for activity G?
Given the following data and network, find answer the questions 18-20 if you're asked to finish this project 2 days earlier than its normal duration. Indirect cost (overhead) is $200 per day. 9.12 E 3 1.8 12. 19 10,13 B 7 1,8 13.20 0,1 1,7 8.15 20,25 15.20 F...
Given the following data and network, find answer the questions 18-20 if you're asked to finish this project 2 days earlier than its normal duration. Indirect cost (overhead) is $200 per day. 9.12 1.8 E 3 12. 19 B 10.13 H 7 1.8 13.20 0.1 1.7 8.15 15.20 20.25 A F I с 6 u K 5 20.25 0.1 8.15 15.20 4. 12 2.8 1.4 D 3 6,9 15.18 G 8 9.17 3 17.20 Duration Normal Crash Days Shortened 7...
what is the normal cost of this project?
what is the cost of the project after 2 days shortening?
what is the crashing cost per day for avtivity G?
Given the following data and network, find answer the questions 18-20 if you're asked to finish this project 2 days earlier than its normal duration. Indirect cost (overhead) is $200 per day. 9.12 E 1.8 اليا 12.19 10.13 B 7 H 7 1.8 13, 20 0.1 1.7 8.15 20,25 15, 20...
Use the moving average method to forecast period 105.Use the exponential smoothing method to forecast period 105.Use the time-series decomposition method to forecast period 105.Comparing the three methods, which one fits this situation best?The larger the parameter (n) is set, the more historical data are taken into account by the moving average.You can choose different parameter (n) to extrapolate to compare the prediction effect.In general, the parameter (n) should not be taken too large.Moving average.153025703560453055106560761085609580106101165012700136701470015760167301776018820197802090021840227702382024800257602676027770287902976030740317203267033690344703567036690376203865039610406204164042590436104460045630466004763048640496105059051610526305366054640558105679057820586505971060700616706269063730647306576066790678106887069890708707189072880739307498075900768607789078880798708084081860829108387084860858408654087780887508978090760917109273093750947509571096750977209877099740100750101760102780103800104850105Exponential smoothingsame153025703560453055106560761085609580106101165012700136701470015760167301776018820197802090021840227702382024800257602676027770287902976030740317203267033690344703567036690376203865039610406204164042590436104460045630466004763048640496105059051610526305366054640558105679057820586505971060700616706269063730647306576066790678106887069890708707189072880739307498075900768607789078880798708084081860829108387084860858408654087780887508978090760917109273093750947509571096750977209877099740100750101760102780103800104850105Time-series decomposition153025703560453055106560761085609580106101165012700136701470015760167301776018820197802090021840227702382024800257602676027770287902976030740317203267033690344703567036690376203865039610406204164042590436104460045630466004763048640496105059051610526305366054640558105679057820586505971060700616706269063730647306576066790678106887069890708707189072880739307498075900768607789078880798708084081860829108387084860858408654087780887508978090760917109273093750947509571096750977209877099740100750101760102780103800104850105
Given below is the crashing data for a project along with other data. The project completion time is 20 davs. Determine: (a) the crash slope (i.e crash cost/day) for all activities, (b) the normal total project cost, (c) prioritized the list of activities for crashing from best to worst, (d) the best activity to crash if the project has to be completed in 19 days and alternative critical paths, if any, (e) the earliest time the project can be completed,...
The Advanced Tech Company has a project to design an integrated information data base for a major bank. Data for the project are given $150 per day. The company will incur a $100 per day penalty for each day the project lasts beyond day 15. the following table. Indirect project costs amount to Normal Time Crash Time Crash Cost Immediate Normal Cost (S) Activity Predecessor(s) (S) (days) (days) 1.200 A 6 800 4 6 1,000 2 2,200 600 900 C...
Data on small maintenance project is given as below: Depend Time Normal Crash Activity on Cost Time Cost 6 days $700 4 days$800 4 days400 5 days 8 days 10 days 200 7 days 3 days600 6 days50 650 625 7 days 250 700 600 s 400 425 days 3 days 500 On completion, the project will give a return of S110day. Using time-cost trade-off method, how much would you like to compress the project for maximiz ng the return?...
Most questions answered within 3 hours.
-
Hi guys! I need help for the Data Structure class i need to
provide implementation of...
asked 5 minutes ago -
Here's what we know:
-companies have lost loyalty from employees due to the quest to
cut...
asked 8 minutes ago -
One way to find prime numbers less than n is to treat them as
array indices....
asked 12 minutes ago -
Consecutive ideal polarizers have axes that are at a 60◦ angle
with respect to each other....
asked 40 minutes ago -
Animals in cold climates often depend on two layers of
insulation: a layer of body fat...
asked 45 minutes ago -
When bond rating companies rate a bond, which are qualities they
evaluate? Pick more than 1...
asked 41 minutes ago -
Please read the following discussion and share your
thoughts and opinions. Ask at least one question....
asked 30 minutes ago -
Describe an experiment to test the assumption that the heat
capacity for the binding of the...
asked 41 minutes ago -
The owner of Genuine Subs, Inc., hopes to expand the present
operation by adding one new...
asked 48 minutes ago -
Find the in-line equilibrium location with respect to two
particles located on the z-axis, the first...
asked 49 minutes ago -
Data from PT Li (in thousand rupiah)
are as follows:
Inventory decrease
90,000
Prepaid expense...
asked 56 minutes ago -
Let X and Y be i.i.d. random variables with finite second
moments. Show that Cov(X+Y, X...
asked 1 hour ago