Question

Task 1
Write a Python program that reads in any number of birth years until the number zero is entered.
The program will then print out the average age and how old the youngest and oldest, respectively.
For this task, you can start from the pseudo-code (separately) you received to get started.
Example of program execution (user entries in numbers (year)):
Enter year of birth. To finish, enter the number 0.
Year: 1998
Year: 1932
Year: 1887
Error: Unreasonable year. Try again.
Year: 1987
Year: -77
Error: Unreasonable year. Try again.
Year: 1963
Year: 0
The average age is 49 years. The youngest is 21 years old and the oldest is 87 years old.

Answer 1

NOTE : I did not get any pseudo code as such. I am writing the code with my logic. Please consider it.

In my code i am accepting the lowest year 1915. I do not know what is the lowest year you have considered in your code.

Code in python3 :

lowest = 115
highest = -100
average = 0
total = 0
entries = 0
print("Enter year of birth. To finish, enter 0")
while True:
print("Year: ")
val = input()
if (int(val) == 0):
break;
if ((int(val) >= 1915)and(int(val)<=2019)):
temp = 2019-int(val)
if (temp < lowest):
lowest = temp
if (temp > highest):
highest = temp
total = total + temp
entries = entries + 1
else:
print("Unreasonable year. Try again")
average = float(total)/entries
print("The average age is ",average,end=".")
print("The youngest is ",lowest," years old and the oldest is ",highest," years old")

Screen shots of written code :

  
PLEASE GIVE THUMBS UP.